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3 years ago

Which are undefined?

Mathematics

2 answers:

iVinArrow [24]3 years ago

7 0

Answer:

Step-by-step explanation:

Ghella [55]3 years ago

6 0

Step-by-step explanation:

I just have a tip to help.

$\frac{0}{k}$ = Ok

$\frac{N}{0}$ =No

If you divide something by zero, (x/0) the answer will be undefined

If you divide zero by something, (0/x) the answer will be zero.

Hope that helped! :D

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Create an equivalent expression that includes a set of parentheses that make the value of the expression 13. Remember, you can h

Ratling [72]

Answer:

(2*9)-5+0

This equals 13.

(8*7)/4-1

This also equals 13.

Hope this helps!

3 0

2 years ago

Which angle is the smallest?

svetoff [14.1K]

Angle A is the smallest.
It's truly simple; The triangle's smallest side is 10 units (used for unknown units of measurements). Angles A and E are both acute angles, however, angle E is larger due to side AD being larger than side ED. So, the angle has to widen in order to reach the full length.

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3 years ago

a water balloon is tossed into the air with an upward velocity of 25 ft/s its height h(t) in ft after t seconds is given by the

Montano1993 [528]

When the height is 0 that is when it hits the ground
solve
0=-16t²+25x+3
cant factor so use quadratic formula

for
0=ax²+bx+c
$x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}$

so for
0=-16t²+25t+3
a=-16
b=25
c=3
so

$x=\frac{-25+/-\sqrt{25^2-4(-16)(3)}}{2(-16)}$
$x=\frac{-25+/-\frac{625+192}}{-32}$
$x=\frac{-25+/-\frac{817}}{-32}$
it has to be a positive time

so it will hit the ground after $\frac{25+\sqrt{817}}{32}$ seconds

4 0

2 years ago

(x+y)^2 where x= 4 and y= -3

Aneli [31]

1 is the answer cccccc

6 0

2 years ago

Read 2 more answers

Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature varies between 73 and 9

Naddika [18.5K]

Answer: After about 9.03 hours the temperature first reach 82 degrees.

Step-by-step explanation:

The sinusoidal function is given by :

$y=A\sin[\omega(x-\alpha)]+C$

where, A = amplitude; $\omega=\dfrac{2\pi}{period}$ , α= phase shift on the Y-axis and C = midline.

As per given,

Average daily temperature= $C=\dfrac{73+97}{2}=85$ [midline is average of upper and lower limit.]

A= 97-85 = 12

Phase shift: $\alpha=10$

Period = 24 hours;

$\omega=\dfrac{2\pi}{24}=\dfrac{\pi}{12}$

Substitute all values in sinusoidal function, we get

$y=12\sin[\dfrac{\pi}{12}(x-10)]+85$

Put y= 82, we get

$82=12\sin[\dfrac{\pi}{12}(x-10)]+85\\\\\Rightarrow\ -3= 12\sin[\dfrac{\pi}{12}(x-10)]\\\\=\dfrac{-1}{4}= \sin[\dfrac{\pi}{12}(x-10)]\\\\\Rightarrow\ \dfrac{\pi}{12}(x-10)=\sin^{-1}(\dfrac{-1}{4})\\\\\Rightarrow\ x-10=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))\\\\\Rightarrow\ x=\dfrac{12}{\pi}(\sin^{-1}(\dfrac{-1}{4}))+10\\\Rightarrow\ x\approx9.03$

Hence, After about 9.03 hours the temperature first reach 82 degrees.

3 0

2 years ago