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2 years ago

I need help finding the Y-intercept

Mathematics

2 answers:

DENIUS [597]2 years ago

7 0

Plug in 0 for x!!!! And do the same for y

luda_lava [24]2 years ago

4 0

2.5 43 dtsuusoqoajshshsjdjhehehehehejjejejatkwdskeywjfesndywirsjr

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Hi can you help me please?)

Ad libitum [116K]

<em>To solve for a variable, you just need to isolate the variable to one side.</em>

For this, just divide both sides by r and <u>your answer will be $\frac{d}{r}=t$ </u>

For this, divide both sides by nR and <u>your answer will be $\frac{PV}{nR}=T$ </u>

Firstly, multiply both sides by T: $AT=FV-OV$

Next, subtract FV on both sides of the equation: $AT-FV=-OV$

Lastly, multiply both sides by -1, and <u>your answer will be $-AT+FV=OV$ </u>

Firstly, multiply both sides by 1000: $1000C=Wtc$

Lastly, divide both sides by tc and <u>your answer will be $\frac{1000C}{tc}=W$ </u>

8 0

3 years ago

Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

Feliz [49]

Your question seems a bit incomplete, but for starters you can write

$\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}$

Expanding where necessary, recalling that $(1-\sin x)(1+\sin x)=1-\sin^2x=\cos^2x$ , you have

$\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}=\dfrac{1+\sin x-\sin x+\sin^2x}{\cos^2x}=\dfrac{1+\sin^2x}{\cos^2x}$

and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

Now, since $1+\tan^2x=\sec^2x$ , the final form could also take

$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

or

$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$

7 0

3 years ago

Error 404.<br> Error 404.

Kitty [74]

Answer:

Error 404

Step-by-step explanation:

404

5 0

2 years ago

16. Factor<br> 40y3 - 625

lina2011 [118]

Answer:

Step-by-step explanation:

prime factorization

40y³ = 2³×5y³

625 = 5⁴

Greatest common factor = 5

40y³ - 625 = 5(8y³ - 125)

Note that 8y³ - 125 is the difference of cubes.

8y³ - 125 = (2y)³ - 5³ = (2y-5)((2y)² + 2y·5 + 5²) = (2y-5)(4y² + 10y + 25)

40y³ - 625 = 5(2y-5)(4y² + 10y + 25)

4 0

2 years ago

Half an avocado has about 160 calories. how many calories do a dozen avocado have

deff fn [24]

160 * 2 = 320 * 12 =

3,840 calories

<em><u>I hope this helped!</u></em>

5 0

3 years ago

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