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3 years ago

Find the area of following rhombuses. Round your answers to the nearest tenth if necessary.

Mathematics

1 answer:

Andrews [41]3 years ago

3 0

Answer:

505.4 in²

Step-by-step explanation:

½d2= 19×tan 35° = 19×0.7 = 13.3 in

d2 = 2×13.3 = 26.6 in

d1 = 2×19=38 in

the area of Rhombus =

½×38×26.6 = 505.4 in²

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(8+24)divided by two to the third power

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For this case we have to:

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Answer:

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Step-by-step explanation:

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3 years ago

RENT? GIVE ME RENT If the mean of six nu m b e rs is 48, does one

bixtya [17]

Answer:

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3 years ago

section of a pipe's length and weight are in proportion. If 2.5 m of pipe weighs 10 kg, then A) 5 m of pipe weighs 30 kg. B) 5 m

motikmotik

We will proceed to resolve each case to determine the solution.

we know that

$2.5$ m of pipe weighs $10$ kg

by proportion

Find the weighs of each case

case A) $5$ m of pipe weighs $30$ kg

$\frac{10}{2.5}\frac{kg}{m}=\frac{x}{5}\frac{kg}{m}\\ \\2.5*x=5*10\\ \\x=50/2.5\\x=20\ kg$

$20\ kg\neq30\ kg$

therefore

The statement case A) is False

case B) $5$ m of pipe weighs $40$ kg

$\frac{10}{2.5}\frac{kg}{m}=\frac{x}{5}\frac{kg}{m}\\ \\2.5*x=5*10\\ \\x=50/2.5\\x=20\ kg$

$20\ kg\neq40\ kg$

therefore

The statement case B) is False

case C) $10$ m of pipe weighs $40$ kg

$\frac{10}{2.5}\frac{kg}{m}=\frac{x}{10}\frac{kg}{m}\\ \\2.5*x=10*10\\ \\x=100/2.5\\x=40\ kg$

$40\ kg=40\ kg$

therefore

The statement case C) is True

case D) $10$ m of pipe weighs $80$ kg

$\frac{10}{2.5}\frac{kg}{m}=\frac{x}{10}\frac{kg}{m}\\ \\2.5*x=10*10\\ \\x=100/2.5\\x=40\ kg$

$40\ kg\neq80\ kg$

therefore

The statement case D) is False

therefore

the answer is

$10$ m of pipe weighs $40$ kg

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3 years ago

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