The two numbers it lies between are 4 and 5
J = 16 solve for j by simplifying both sides of the equation, then isolating the variable
Answer:
q = 2
Step-by-step explanation:
0.5-0.125q=(q-1)/4
At first, we have to multiply both the sides by 4.
4 × (0.5 - 0.125q) = q - 1
or, 2 - 0.5q = q - 1
now, we change the side by taking constant into the right side and the number into the left side.
2 + 1 = q + 0.5q
or, 3 = q (1 + 0.5)
or, 3 = 1.5 q
or, 1.5 q = 3
or, 
= (3 ÷ 1.5) [Dividing both the sides by 1.5]
or, q = 2
Therefore, q = 2
Answer:
A
Step-by-step explanation:
-3x²y² × y⁴x³
When multiplying, add the exponents:
-3x⁽²⁺³⁾y⁽²⁺⁴⁾
-3x⁵y⁶
Answer is A.
Answer:
Original number 26.
Step-by-step explanation:
xy - two-digit number
1) x + y = 8
2) Original two-digit number can be written as
10*x + y
3) If the digits interchanged yx,
then the new number can be written as
10*y + x
4) Double the original number is
2*(10*x + y)
5) New number is 10 more than double the original number
(10*y + x) - (2*(10*x + y)) = 10
6) Now we have the system of 2 equations:
x + y = 8
(10*y + x) - (2*(10*x + y)) = 10 -----> 10y + x - (20x + 2y) = 10 ---> 8y - 19x = 10
x = 8 - y
8y - 19(8 - y) = 10
8y - 152 +19y = 10
27y = 162
y = 6
x = 8 - y = 8 - 6 = 2
x = 2
So, x =2, y = 6.
Original number 26.
Check:
Original number 26.
New number 62.
Double of the original number = 2*26= 52.
New number is 10 more than double the original number :
62 - 52 = 10 True
