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3 years ago

10

The picture below shows a container that Rene uses to freeze water: A cylinder is shown with base diameter of 6 centimeters and

the height as 8 centimeters. What is the minimum number of identical containers that Rene would need to make 2,000 cm3 of ice? (Use π = 3.14.) 27 9 14 20

2 answers:

Nat2105 [25]3 years ago

7 0

Answer:

9

Step-by-step explanation:

Given : A cylinder is shown with base diameter of 6 centimeters and the height as 8 centimeters.

To Find: What is the minimum number of identical containers that Rene would need to make 2,000 cubic cm of ice.

Solution :

Diameter of container = 6 cm

Radius = Diameter/2 = 6/2 = 3 cm

Height of container = 8 cm

Volume of cylinder = $\pi r^{2} h$

Where r is the radius

h is the height.

So, volume of the container = $\pi\times 3^{2} \times 8$

= $3.14\times 3^{2} \times 8$

= $226.08$

Rene would need to make 2,000 cubic cm of ice.

So, no. of containers required = $\frac{\text{Volume of ice}}{\text{Volume of container}}$

= $\frac{2000}{226.08}$

= $8.84$

So, no. of containers required = 8.84 ≈ 9.

Hence the minimum number of identical containers that Rene would need to make 2,000 cubic cm of ice is 9

Rama09 [41]3 years ago

4 0

it would be 9.

2000/226.2 = 8.84 == 9

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