Some basic formulas involving triangles
\ a^2 = b^2 + c^2 - 2bc \textrm{ cos } \alphaa  2 =b  2+2 + c 2
 −2bc cos α
\ b^2 = a^2 + c^2 - 2ac \textrm{ cos } \betab   2=
  
m_b^2 = \frac{1}{4}( 2a^2 + 2c^2 - b^2 )m   b2 = 41(2a 2 + 2c 2-b 2)
b
Bisector formulas
\ \frac{a}{b} = \frac{m}{n}  ba =nm  
  
  
\ l^2 = ab - mnl  2=ab-mm
 A = \frac{1}{2}a\cdot b = \frac{1}{2}c\cdot hA=  
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=  
p(p−a)(p−b)(p−c)
  
  
\iits whatever  A = prA=pr with r we denote the radius of the triangle inscribed circle
\ A = \frac{abc}{4R}A=  
4R
abc
  
  - R is the radius of the prescribed circle
\ A = \sqrt{p(p - a)(p - b)(p - c)}A=  
p(p−a)(p−b)(p−c)
  
 
        
             
        
        
        
To find the answer to -10x=-210 you must divide -210 by -10
-210/-10= 21
Therefore x=21 
So the proper equation is -10(21)=-210
 
 
        
                    
             
        
        
        
Answer:C
Step-by-step explanation:Just did it on apex and got it correct ✋:)
 
        
             
        
        
        
Answer: 2^7
Step-by-step explanation: 2 to the power of 7 would be one of the many ways to interact with this equation. This way being the exponential response. (Check your sources before this answer.)