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2 years ago

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Evaluate M/N for M=10, N=-5, and P =-2

1 answer:

Leno4ka [110]2 years ago

8 0

The answer is 2.

You would replace the letters with number which it would be 10/5

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Find dy/dx if y =x^3+5x+2/x²-1

stiks02 [169]

<u>Differentiate using the Quotient Rule</u> –

$\qquad$ $\pink{\twoheadrightarrow \sf \dfrac{d}{dx} \bigg[\dfrac{f(x)}{g(x)} \bigg]= \dfrac{ g(x)\:\dfrac{d}{dx}\bigg[f(x)\bigg] -f(x)\dfrac{d}{dx}\:\bigg[g(x)\bigg]}{g(x)^2}}\\$

According to the given question, we have –

f(x) = x^3+5x+2
g(x) = x^2-1

Let's solve it!

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{d}{dx}\bigg[ \dfrac{x^3+5x+2 }{x^2-1}\bigg]} \\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1) \dfrac{d}{dx}(x^3+5x+2) - ( x^3+5x+2) \dfrac{d}{dx}(x^2-1)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{(x^2-1)(3x^2+5) - ( x^3+5x+2) 2x}{(x^2-1)^2 }\\$

$\qquad$ $\pink{\sf \because \dfrac{d}{dx} x^n = nx^{n-1} }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-(2x^4+10x^2+4x)}{(x^2-1)^2 }\\$

$\qquad$ $\twoheadrightarrow \sf \dfrac{3x^4+5x^2-3x^2-5-2x^4-10x^2-4x}{(x^2-1)^2 }\\$

$\qquad$ $\green{\twoheadrightarrow \bf \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}\\$

$\qquad$ $\pink{\therefore \bf{\green{\underline{\underline{\dfrac{d}{dx} \dfrac{x^3+5x+2 }{x^2-1}} = \dfrac{x^4-8x^2-4x-5}{(x^2-1)^2 }}}}}\\\\$

7 0

1 year ago

Lol im going to fail someone pls help

lidiya [134]

4.50 and 8 I think the answer is

7 0

2 years ago

Read 2 more answers

Which of the points listed below is not on the line with equation 7y+2=3x-5

kicyunya [14]

Answer: Second option.

Step-by-step explanation:

Given the folllowing Linear Equation:

$7y+2=3x-5$

You need to substitute the coordinates of each point given in the options into the equation and then evaluate.

1) Substituting $(2, -\frac{1}{7})$ into the equation, you get:

$7(-\frac{1}{7})+2=3(2)-5\\\\-1+2=6-5\\\\1=1\ (TRUE)$

2) Substituting the point $(3, -\frac{3}{7})$ . you get:

$7(-\frac{3}{7})+2=3(3)-5\\\\-3+2=9-5\\\\-1=4\ (FALSE)$

3) Apply the same procedure using the point $(1, -\frac{4}{7})$ :

$7(-\frac{4}{7})+2=3(1)-5\\\\-4+2=3-5\\\\-2=-2\ (TRUE)$

4) Apply the same procedure using the point $(-1, -\frac{10}{7})$

$7(-\frac{10}{7})+2=3(-1)-5\\\\-10+2=-3-5\\\\-8=-8\ (TRUE)$

5) Substituting $(0,-1)$ into the equation:

$7(-1)+2=3(0)-5\\\\-7+2=-0-5\\\\-5=-5\ (TRUE)$

Therefore, the point $(3, -\frac{3}{7})$ is not on the given line.

8 0

3 years ago

Select the correct answer which function is increasing at the highest rate?

saw5 [17]

Answer:

D.since the gragh is linear

4 0

2 years ago

What percent of 42 is 30? In proper fraction

olga55 [171]

The answer is 500/7
Hope this helps

6 0

2 years ago

Read 2 more answers