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2 years ago

Find four consecutive whole numbers whose sum is 74

Mathematics

2 answers:

Tju [1.3M]2 years ago

5 0

Answer:

17, 18, 19, 20

Step-by-step explanation:

Let four consecutive whole numbers be x, (x + 1), (x + 2) and (x + 3)

According to the given condition:

x + (x + 1) + (x + 2) + (x + 3) = 74

-> 4x + 6 = 74

-> 4x = 74 - 6

-> 4x = 68

-> x = 68/

-> x = 17

-> x + 1 = 17 + 1 = 18

-> x + 2 = 17 + 2 = 19

-> x + 3 = 17 + 3 = 20

Thus, the four consecutive whole numbers are 17, 18, 19 and 20

Rina8888 [55]2 years ago

4 0

Answer:

17, 18, 19, 20

Explanation:

Let the numbers be x, x + 1, x + 2, x + 3

Their sum is equals to 74

x + x + 1 + x + 2 + x + 3 = 74 (group the variables)

x + x + x + x + 1 + 2 + 3 = 74 (simplify)

4(x) + 6 = 74 (subtract both sides by 6)

4x = 68 (divide both sides by 4)

x = 17

Other numbers:

x + 1 = 17 + 1 = 18

x + 2 = 17 + 2 = 19

x + 3 = 17 + 3 = 20

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Find four consecutive whole numbers whose sum is 74​

Find four consecutive whole numbers whose sum is 74