Question

Find four consecutive whole numbers whose sum is 74​

Answer 1

Answer:

17, 18, 19, 20

Step-by-step explanation:

• Let four consecutive whole numbers be x, (x + 1), (x + 2) and (x + 3)

• According to the given condition:

• x + (x + 1) + (x + 2) + (x + 3) = 74

• -> 4x + 6 = 74

• -> 4x = 74 - 6

• -> 4x = 68

• -> x = 68/

• -> x = 17

• -> x + 1 = 17 + 1 = 18

• -> x + 2 = 17 + 2 = 19

• -> x + 3 = 17 + 3 = 20

• Thus, the four consecutive whole numbers are 17, 18, 19 and 20

Answer 2

Answer:

17, 18, 19, 20

Explanation:

Let the numbers be x, x + 1, x + 2, x + 3

Their sum is equals to 74

x + x + 1 + x + 2 + x + 3 = 74     (group the variables)

x + x + x + x + 1 + 2 + 3 = 74    (simplify)

4(x) + 6 = 74                             (subtract both sides by 6)

4x = 68                                     (divide both sides by 4)

x = 17

Other numbers:

x + 1 = 17 + 1 = 18

x + 2 = 17 + 2 = 19

x + 3 = 17 + 3 = 20