Evaluat the expression 202-[2(3+7)+6]=

Mathematics

1 answer:

valina [46]3 years ago

6 0

You need to start calculating from the innermost bracket and if there are no signs to do any operation then you need to multiply

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Tom opens a bank account and makes an initial deposit of 500$. Then banker tells Tom that he is going to receive an annual rate

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$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$500\\ r=rate\to 6\%\to \frac{6}{100}\dotfill &0.06\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &15 \end{cases} \\\\\\ A=500\left(1+\frac{0.06}{1}\right)^{1\cdot 15}\implies A=500(1.06)^{15}\implies A\approx 1198.28$

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irina [24]

I mean, I don't know how to explain a generic way to solve this. Ask me about the specific train of thought if you are interested:

7 * 18 + 45 / 3 - 2 = 139

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Answer:

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Step-by-step explanation:

3 7/10 - 2 2/5 =

3 7/10 - 2 4/10 =

1 3/10

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Evaluat the expression 202-[2(3+7)+6]=​

Evaluat the expression 202-[2(3+7)+6]=