Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11
Answer:
The definition including its given problem is outlined in the following segment on the clarification.
Explanation:
- Entity-relationship (ER) diagram describes how mechanical stored procedures are constructed and demonstrate the overarching representation of the situation. It also describes the connections between some of the entities of the framework and even the comparison with standard measurements.
- For something like an individual relationship structure, the normal representation of connections seems to be a diamond. Associative institutions have several to many partnerships to communicate with. It's indeed the verb throughout a diamond-shaped form that holds two organizations around each other. This verb is in fact an entity on its own, therefore it must be termed an associative entity.
- An illustration of such might be if a participant were to register for a class. Multiple individuals will be registered for several courses, and there have been many to several relationships; thus, the associative object will indeed register.
Here's some code that might help, assuming that you are using JavaScript.
e = "Hello"
if(e === "Hello"){
alert(":D")
}else{
console.log("Um.")
}
I think that the answer is curly brackets.
Answer:
1 2 3 4 5 6 7 8 End
Explanation:
int i = 1;
while (i != 9){
System.out.print (i + " ");
i ++;
if (i == 9){
System.out.println("End");
}
}
