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mamaluj [8]
1 year ago
9

The following image shows the number of orders Company A received in 2015-2020. A financial analyst wants to calculate the year-

over-year growth rate of the orders and has entered the formula for 2016 in cell C4. What steps should the analyst take to apply the same formula to all adjacent years using the Macabacus’ Fast Fill Right shortcuts?
Computers and Technology
1 answer:
abruzzese [7]1 year ago
8 0

The step that the analyst take to apply the same formula to all adjacent years using the Macabacus’ Fast Fill Right shortcuts  is the use of the  Macabacus Excel Add-in.

<h3>What are the feature in the Formulas menu of the Macabacus Excel add-in?</h3>

The Macabacus Excel Add-in is known to be a formula auditing tools that aids  one to be able to know and correct any kinds of errors and other forms of inconsistencies in the financial models.

Note that it is one that tends to bring up the speed of the modeling process. The Excel add-in is a tool that aid the users to make some reliable links between the financial model and that of the PowerPoint or Word documents.

Hence, The step that the analyst take to apply the same formula to all adjacent years using the Macabacus’ Fast Fill Right shortcuts  is the use of the  Macabacus Excel Add-in.

Learn more about Macabacus from

brainly.com/question/1538272

#SPJ1

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C. an example of open-source software.

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You have been asked to write a username validation program for a small website. The website has specific rules on what constitut
umka21 [38]

Answer:

#function to validate username

def valid_username(username):

   

   #checking is length is between 8 to 15

   length_valid=True

   if(len(username)<8 or len(username)>15):

       length_valid=False;

   

   #checking is string is alphanumeric

   alphanumeric=username.isalnum()

   

   #checking first_and_last Characters of string is not digit

   first_and_last=True

   if(username[0].isdigit() or username[len(username)-1].isdigit()):

       first_and_last=False

   

   #counting uppercase lowercase and numeric Characters in string

   uppercase=0

   lowercase=0

   numeric=0

   

   for i in username:

       if(i.isdigit()):

           numeric=numeric+1

       elif(i.isalpha()):

           if(i.isupper()):

               uppercase=uppercase+1

           else:

               lowercase=lowercase+1

               

   valid_no_char=True

   if(uppercase<1 or lowercase<1 or numeric<1):

       valid_no_char=False

           

 

   #printing the result

   print("Length of username: "+str(len(username)))

   print("All Characters are alpha-numeric: "+str(alphanumeric))

   print("First and last Character are not digit: "+str(first_and_last))

   print("no of uppercase characters in the username: "+str(uppercase))

   print("no of lowercase characters in the username: "+str(lowercase))

   print("no of digits in the username: "+str(numeric))

   

   #checking string is Valid or not

   if(length_valid and alphanumeric and first_and_last and valid_no_char):

       print("Username is Valid\n")

       return True

   else:

       print("username is invalid, please try again\n")

       return False

#loop runs until valid_username enterd by user

while(True):

   

   username=input("Enter a username: ")

   if(valid_username(username)):

       break

Explanation:

The code was created by considering all the required cases asked in the question.

In this program, I asked username from the user continuously until it enters a valid username

first it check for length of string

then check is string contains only alphanumeric characters

then first and last digit is or not

than no of uppercase lowercase and numeric character

using the above parameter declare username valid or not

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