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Rashid [163]
3 years ago
9

I need the answer key to all they questions. The book is Digits. Lesson 11 Unit 5 Angle- Angle Triangle Similarity. Who can help

?

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0
Go to slader online and try to look up your textbook for the answers to all the questions
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Identify the Domain and Range of the graph below:<br><br><br> Domain: <br> Range:
Nuetrik [128]
Domain is all real numbers
Range i forgot I’m sorry
5 0
3 years ago
The Sydney cricket ground can contain a football field of approximately 147m by 136m. What distance would be covered by walking
Irina-Kira [14]
The answer is 566m because 147 plus 147 and 136 plus 136 equals 566
7 0
3 years ago
What is the value of ln e^4
sineoko [7]

Answer:

\large\boxed{\ln e^4=4}

Step-by-step explanation:

Use\\\\\log_ab^n=n\log_ab\\\\\log_aa=1\\\\\ln a=\log_e a\to\ln e=1\\====================================\\\\\ln e^4=4\ln e=4(1)=4

3 0
3 years ago
A sample size 25 is picked up at random from a population which is normally
Margarita [4]

Answer:

a) P(X < 99) = 0.2033.

b) P(98 < X < 100) = 0.4525

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 100 and variance of 36.

This means that \mu = 100, \sigma = \sqrt{36} = 6

Sample of 25:

This means that n = 25, s = \frac{6}{\sqrt{25}} = 1.2

(a) P(X<99)

This is the pvalue of Z when X = 99. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{99 - 100}{1.2}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033. So

P(X < 99) = 0.2033.

b) P(98 < X < 100)

This is the pvalue of Z when X = 100 subtracted by the pvalue of Z when X = 98. So

X = 100

Z = \frac{X - \mu}{s}

Z = \frac{100 - 100}{1.2}

Z = 0

Z = 0 has a pvalue of 0.5

X = 98

Z = \frac{X - \mu}{s}

Z = \frac{98 - 100}{1.2}

Z = -1.67

Z = -1.67 has a pvalue of 0.0475

0.5 - 0.0475 = 0.4525

So

P(98 < X < 100) = 0.4525

6 0
3 years ago
if your bicycle tire has a diameter of 9 inches. how many rotations does each tire make if you travel 300 feet?
Vesnalui [34]
Step One
Calculate the number of feet traveled in 1 rotation.

Formula
C = π*d
P = 3.14
d = 9 inches = 9/12 feet = 3/4 of a foot.

C = 3.14 * 3/4 = 2.355 So that means that every time the tire turns around 1 complete turn, the distance traveled on the ground is 2.355 feet.
 
Step Two
Figure out the number of revolutions.
1 revolution = 2.355 feet
x revolutions = 300 feet.

1/x = 2.355/ 300  Cross multiply
2.355 feet * x = 1 rev * 300 feet
2.355 x = 300 rev Divide by 2.355
x = 300 / 2.355 
x = 127.39 revolutions. <<<< Answer

8 0
3 years ago
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