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klemol [59]
3 years ago
14

Setup a rational equation and solve it from the word problem. Mr. Solberg can ride his scooter 3 miles against the wind in the s

ame time it takes him to scooter 4 miles with the wind. If the speed of the wind is 5 mile per hour, how fast does Mr. Solberg scooter when there is no wind?
Mathematics
1 answer:
dolphi86 [110]3 years ago
7 0

Answer:

The speed of Mr Solberg's scooter when there is no wind is 35 miles per hour

Step-by-step explanation:

The given parameters are;

The time Mr. Solberg rides his scooter and cover 3 miles against the wind = The time Mr. Solberg rides his scooter and cover 4 miles with the wind

The speed of the wind = 5 miles per hour

Let v, represent the speed of Mr Solberg's scooter when there is no wind, we have;

Time = Distance/Speed

Mr Solberg's speed against the wind = v - 5

Mr Solberg's speed with the wind = v + 5

The distance covered at a given time, while riding against the wind = 3 miles

The distance covered at the same time, while riding with the wind = 4 miles

The time in both instances are therefore 3/(v - 5) = 4/(v + 5)

From which we have;

3 × (v + 5) = 4 × (v - 5)

3·v + 15 = 4·v - 20

20 + 15 = 4·v - 3·v

4·v - 3·v = 20 + 15

v = 35

The speed of Mr Solberg's scooter when there is no wind = v = 35 miles per hour.

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Subtract 85.915 by 12.88725. You should get 73.02775.

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3 years ago
An object is moved at a constant speed of 20m/s for 4s
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The parabola x = y2 - 9 opens:
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Which graph best represents an exponential function?
stellarik [79]

Hey there! :)

Answer:

Choice B.

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We can eliminate each graph:

a). This is what is known as a step function. This is incorrect.

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c). This is an absolute value function. This is incorrect.

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Which of the following equations could be th equation to represent the given graph? Make sure you explain your answer thoroughly
Alex17521 [72]

Answer:

Option (C) is correct.

Step-by-step explanation:

The given options of the possible equation for the graph are as follows:

(A) y=2\left(\frac{3}{2}\right)^x \\\\(B) y=-2\left(\frac{3}{2}\right)^{-x} \\\\(C) y=2\left(\frac{2}{3}\right)^x \\\\(D) y=-2\left(\frac{2}{3}\right)^{-x} \\\\

The given graph is decreasing and at x=0, y=2.

So, first checking the value of the given options for x=0

(A) y=2\left(\frac{3}{2}\right)^0=2\times 1= 2 \\\\(B) y=--2\left(\frac{3}{2}\right)^{-0}= -2\times 1= -2 \; (not\; possible) \\\\(C) y=2\left(\frac{2}{3}\right)^0= 2\times 1= 2 \\\\(D) y=2\left(\frac{2}{3}\right)^{-0} = -2\times 1= -2 \; (not\; possible)

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For option (A),

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As \ln \left(\frac{2}{3}\right)=\ln(0.67)0

So, \frac{dy}{dx}

Therefore, the function in option (C) is decreasing function.

As the given graph is decreasing, so, (C)  representsy=2\left(\frac{2}{3}\right)^x the given graph.

Hence, option (C) is correct.

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