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Olegator [25]
2 years ago
11

Hey everybody! Can anybody help me out with this algebra problem? I would really appreciate it if you can!

Mathematics
1 answer:
umka2103 [35]2 years ago
4 0

Answer:

x and y are directly related because y = -3x

Step-by-step explanation:

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Can you answer my question
Whitepunk [10]

Answer:

Yup........ I will try.......

8 0
3 years ago
During a concert, $3280 was received. A total of 760 people attended. Reserved seats were $6 and general admission seats were $4
Andre45 [30]

Answer:

The number of reserved seat is 120 and number of general seat is 640.

Step-by-step explanation:

Given,

Total number of seats = 760

Total collected Money = $3280

Solution,

Let the total number of reserved seat be x.

And  the total number of general seat be y

Hence total number of seats is the sum of total number of reserved seat and  the total number of general seats.

So the equation can be written as;

x+y=760\ \ \ \ equation\ 1

Again, total money collected is the sum of fees of one reserved seat times total number of reserved seat and fees of one general seat times the total number of general seats.

So the equation can be written as;

6x+4y=3280\ \ \ \ \ equation\ 2

Now, multiplying equation 1 by 4 and then subtract it from equation 2.

4x+4y=3040

(6x+4y)-(4x+4y)=3280-3040\\\\2x=240\\\\x=\frac{240}{2}=120

On substituting the value of x in equation 1, we get;

x+y=760\\120+y=760\\y=760-120=640

Thus the number of reserved seat is 120 and number of general seat is 640.

8 0
2 years ago
Find the side of a cube if its volume is 1331 cm³.​
SSSSS [86.1K]

answe= aprox 11

Using the formula

V=a3

Solving fora

a=V⅓=1331⅓≈11

4 0
2 years ago
A gumball machine has just been filled with 50 black, 150 white, 100 red and 100 yellow gum balls that have been thoroughly mixe
Andrew [12]
<span>Exactly 33/532, or about 6.2% This is a conditional probability, So what we're looking for is the probability of 2 gumballs being selected both being red. So let's pick the first gumball. There is a total of 50+150+100+100 = 400 gumballs in the machine. Of them, 100 of the gumballs are red. So there's a 100/400 = 1/4 probability of the 1st gumball selected being red. Now there's only 399 gumballs in the machine and the probability of selecting another red one is 99/399 = 33/133. So the combined probability of both of the 1st 2 gumballs being red is 1/4 * 33/133 = 33/532, or about 0.062030075 = 6.2%</span>
6 0
3 years ago
Carlos ran 7 miles in 57 minutes. How fast did he run each mile ? June runs a little slower then Carlos. She ran one fourth of a
skad [1K]
57/7=8.14 so Carols ran 1 mile in 8.14 minutes
3*4=12 so June can run 1 mile in 12 minutes
7 0
3 years ago
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