Tom has some marbles in two bags. In one bag he has 3 yellow, 2 green and 1 red marble. In the other bag he has 3 yellow, 3 gree
n and 3 red marbles. If Tom takes one marble out of each bag, how probable is it that neither one is yellow? Include a chart of all the data you have.
1 answer:
Answer:
1 / 3
Step-by-step explanation:
Bag 1 :
Yellow = 3
Green = 2
Red = 1
Total = 3 + 2 +1 = 6
Bag 2 :
Yellow = 3
Green = 3
Red = 3
Total = 3 + 3 + 3 = 9
P(not yellow from bag 1) = (green + red) / total = 3 /6 = 1/2
P(not yellow from bag 2) = (green + red) / total = 6/9 = 2 /3
P(neither is yellow) = 1/2 * 2/3 = 2 / 6 = 1/3
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