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NISA [10]
3 years ago
5

D= kA [T2 - T1 / L] Solve for T1

Mathematics
1 answer:
mel-nik [20]3 years ago
5 0
d=\dfrac{k_A(T_2-T_1)}{T}\ \ \ \ |multiply\ both\ sides\ by\ T\\\\k_A(T_2-T_1)=dT\ \ \ \ |divide\ both\ sides\ by\ k_A\\\\T_2-T_1=\dfrac{dT}{k_A}\ \ \ \ |subtract\ T_2\ from\ both\ sides\\\\-T_1=\dfrac{dT}{k_A}-T_2\ \ \ \ \ |change\ signs\\\\\boxed{T_1=T_2-\frac{dT}{k_A}}
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<h3>How to solve the equation?</h3>

The equation is given as:

one-third (x + 9) = negative 12

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1/3 (x + 9) = -12

Multiply both sides by 3

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Hence, the solution to the equation one-third (x + 9) = negative 12 is  x = -45

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brainly.com/question/14323743

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