(3x^5y)^2=
3^2=9
(x^5)^2=x^10
y^2=y^2
(3x^5y)^2=9x^10y^2
9x^10y^2(4x^3y^5)=
9*4=36
x^10*x^3=x^13
y^2*y^5=y^7
9x^19y^2(4x^3y^5)= 36x^13y^7
Final answer: B
Answer:
B. x^2-10
Step-by-step explanation:
Your are trying to find the shaded region
You can see that the x by x square would be "full" if not for the 2 by 5 chunk that has been taken out of it
Therefore you can find the area by subtracting the 2 by 10 "chunk" out of the total area of the x by x square
Equation:
(x*x)-(2*5)
x^2-10
The answer is B
Answer: s=36
Step-by-step explanation:
To solve for s, we can use our algebraic properties to solve.
[subtract both sides by 14]
[multiply both sides by 3]


means to say that for any given
, we can find
such that anytime
(i.e. the whenever
is "close enough" to 5), we can guarantee that
(i.e. the value of
is "close enough" to the limit value).
What we want to end up with is

Dividing both sides by 3 gives

which suggests
is a sufficient threshold.
The proof itself is essentially the reverse of this analysis: Let
be given. Then if

and so the limit is 7. QED
Answer:
60.00
Step-by-step explanation:
49.75 + 15%(7.46) = 57.21