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noname [10]
3 years ago
6

TRI has vertices T(-3, 4), R(3, 4), and I(0,0). Is TRI scalene, isosceles, or equilateral?

Mathematics
1 answer:
KatRina [158]3 years ago
4 0

Answer:

Isosceles

Step-by-step explanation:

Graph your triangle!

Then, do the distance formula. So from T to I is 5 units, R to I is 5 units, and T to R is 6 units. As two side lengths are congruent, the triangle is isosceles.

Hope this helps!


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Which inequality is graphed on the coordinate plane?​
bekas [8.4K]

Answer:

a

Step-by-step explanation:

1:cancel out any answers with equal to since the line is dotted

2:pick any two points of your choice and work out the gradient

3:use the gradient a point on the line and an anonymous point (x,y) to get equation of a line

4:then choose a point (0,0) and substitute x with 0 in the equation to get y (in this case it's -1) which is less than 0 hope it helps

5 0
3 years ago
How do you do these two questions?
Mice21 [21]

Answer:

a) d²y/dx² = ½ x + y − ½

b) Relative minimum

Step-by-step explanation:

a) Take the derivative with respect to x.

dy/dx = ½ x + y − 1

d²y/dx² = ½ + dy/dx

d²y/dx² = ½ + (½ x + y − 1)

d²y/dx² = ½ x + y − ½

b) At (0, 1), the first and second derivatives are:

dy/dx = ½ (0) + (1) − 1

dy/dx = 0

d²y/dx² = ½ (0) + (1) − ½

d²y/dx² = ½

The first derivative is 0, and the second derivative is positive (concave up).  Therefore, the point is a relative minimum.

4 0
3 years ago
Can someone please help me on solving: x+y=-4
timama [110]

Answer: x=-1 and y= -3

Step-by-step explanation:

Solve for x, x+y=-4

Minus y from both sides so it'll be X=-y-4

Now substitute -y-4 in x-y=2 and solve for y

-y - 4 -y=2

Add like terms, -2y - 4=2

Add 4 to both sides -2y=6

Divide both sides by -2 \frac{-2y}{-2} = \frac{6}{-2}

y= -3

Substitute -3 in x=-y - 4

x=-(-3) - 4

- × (-3)= 3

3 - 4= -1

x= -1

5 0
2 years ago
Th sum of the cost of dinner d a $12 tip divided equally between 3 people
Bond [772]
12 / 3 so the answer would be 4
5 0
3 years ago
Find the equation of the line through (-9,6) that is perpendicular to the line through (7,8),
Setler [38]

Step-by-step explanation:

I assume as "equation" we mean the slope-intercept form :

y = ax + b

"a" is the slope of the line (y coordinate change / x coordinate change when going from one point to another on the line). b is the y-intercept (the y value when x = 0).

we get the slope by finding the perpendicular slope of the first line.

the slope of the first line when going from (-3, -9) to (7, 8) :

x changes by + 10 (from -3 to +7).

y changes by + 17 (from -9 to +8).

so, that slope is 17/10.

the perpendicular slope is turning the original slope upside-down and flips the sign :

-10/17

so, a = -10/17

now, as we have only the slope and a point of the new line, we can use the point-slope form to stay and then transfer into the slope-intercept form.

y - y1 = a(x - x1)

where "a" is again the slope, and (x1, y1) is a point on the line

y - -6 = -10/17 × (x - -9)

y + 6 = -10/17 × (x + 9) = -10/17 × x - 90/17

y = -10/17 × x - 90/17 - 6 =

= -10/17 × x - 90/17 - 102/17 =

= -10/17 × x - 192/17

so, the equation is (in a maybe nicer way)

y = -1/17 × (10x + 192)

7 0
1 year ago
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