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3 years ago

6

TRI has vertices T(-3, 4), R(3, 4), and I(0,0). Is TRI scalene, isosceles, or equilateral?

1 answer:

KatRina [158]3 years ago

4 0

Answer:

Isosceles

Step-by-step explanation:

Graph your triangle!

Then, do the distance formula. So from T to I is 5 units, R to I is 5 units, and T to R is 6 units. As two side lengths are congruent, the triangle is isosceles.

Hope this helps!

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Troyanec [42]

to find the x-intercept of a function, we simply set y = 0 and then solve for "x", so, let's first find the equation of it and then set y = 0.

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3 years ago

Sophie has 5 pieces of string that are each 5 feet long. Cooper has 4 pieces of string that are each

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Answer:

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Step-by-step explanation:

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3 years ago

The diameter of a regulation socver ball is about 8 3/5 inches. This number was graphed on a number line. Which point could be p

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3 years ago

Corinna's cell phone bill was $52.75 in July.

rodikova [14]

Answer:

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Explanation:

If her bill in July was $52.75 and her bill in August was only 60% of July

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hope this helps!

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3 years ago

What is the center of the ellipse x2+5y2–45=0?

jeka94

Answer:

Center is at (0,0)

Step-by-step explanation:

An equation of ellipse in standard form is:

$\displaystyle{\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2} = 1$

Where center is at point (h,k)

From the equation of $\displaystyle{x^2+5y^2-45=0}$ . First, we add 45 both sides:

$\displaystyle{x^2+5y^2-45+45=0+45}\\\\\displaystyle{x^2+5y^2=45}$

Convert into the standard form with RHS (Right-Hand Side) equal to 1 by dividing both sides by 45:

$\displaystyle{\dfrac{x^2}{45}+\dfrac{5y^2}{45}=\dfrac{45}{45}}\\\\\displaystyle{\dfrac{x^2}{45}+\dfrac{y^2}{9}=1}$

Therefore, the center of ellipse is at (0,0) since there are no values of h and k.

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2 years ago