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2 years ago

Rewrite this equation so that it demonstrates the division property of equality: 12m=42

Mathematics

2 answers:

elixir [45]2 years ago

8 0

Answer:
12m ÷ 12 = 42 ÷ 12

alexandr402 [8]2 years ago

8 0

Answer:

m=30

Step-by-step explanation:

subtract or divide 12 from 12 and 42, then you're left with m and 32. m=32

12m=42

-12. -12.

m. 30

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Richard has enrolled in a 401(k) savings plan. He intends to deposit $250 each month; his employer does not contribute to his ac

astraxan [27]

Answer:

Richard will have $60,000 in his account in 20 years.

Step-by-step explanation:

(1) Multiply $250 x 12

(2) Multiply the answer of $250 x 12 which is 3000 by 20

(3) Final answer would be $60,000

7 0

3 years ago

A representative from the National Football League's Marketing Division randomly selects people on a random street in Kansas Cit

Orlov [11]

Using the binomial distribution, we have that:

a) 0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

b) 0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

c) The expected number of people is 4, with a variance of 20.

For each person, there are only two possible outcomes. Either they attended a game, or they did not. The probability of a person attending a game is independent of any other person, which means that the binomial distribution is used.

Binomial probability distribution

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

p is the probability of a success on a single trial.

n is the number of trials.

p is the probability of a success on a single trial.

The expected number of trials before q successes is given by:

$E = \frac{q(1-p)}{p}$

The variance is:

$V = \frac{q(1-p)}{p^2}$

In this problem, 0.2 probability of a finding a person who attended the last football game, thus $p = 0.2$ .

Item a:

None of the first three attended, which is P(X = 0) when n = 3.
Fourth attended, with 0.2 probability.

Thus:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{3,0}.(0.2)^{0}.(0.8)^{3} = 0.512$

$0.2(0.512) = 0.1024$

0.1024 = 10.24% probability that the marketing representative must select 4 people to find one who attended the last home football game.

Item b:

This is the probability that none of the first six went, which is P(X = 0) when n = 6.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.2)^{0}.(0.8)^{6} = 0.2621$

0.2621 = 26.21% probability that the marketing representative must select more than 6 people to find one who attended the last home football game.

Item c:

One person, thus $q = 1$ .

The expected value is:

$E = \frac{q(1-p)}{p} = \frac{0.8}{0.2} = 4$

The variance is:

$V = \frac{0.8}{0.04} = 20$

The expected number of people is 4, with a variance of 20.

A similar problem is given at brainly.com/question/24756209

3 0

1 year ago

What is the definition of symbolism?

notka56 [123]

Answer:

The use of symbols to represent ideas or qualities.

5 0

3 years ago

The expression p/x^2 - 5x +6 simplifies to x+4/x-2. Which expression doees p represent?

gladu [14]

We know that
(ad)/(bd)=d/d time a/b=a/b since d's cancel
also
if a/b=c/d in simplest form, then a=c and b=d

we have
p/(x^2-5x+6)=(x+4)/(x-2)
therefor

p/(x^2-5x+6)=d/d times (x+4)/(x-2)
p/(x^2-5x+6)=d(x+4)/d(x-2)

therefor
p=d(x+4) and
x^2-5x+6=d(x-2)

we can solve last one
factor
(x-6)(x+1)=d(x-2)
divide both sides by (x-2)
[(x-6)(x+1)]/(x-2)=d
sub

p=d(x+4)
p=([(x-6)(x+1)]/(x-2))(x+4)
$p= \frac {(x-6)(x+1)(x+4)}{(x-2)}$

7 0

3 years ago

A square root is categorized as what kind of number? Choices: Irrational Rational

anyanavicka [17]

Rational i believe is the answer i ain't for sure though

6 0

3 years ago