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egoroff_w [7]
3 years ago
10

How do i solve 3x+4-x=5x-16-7x?

Mathematics
2 answers:
rosijanka [135]3 years ago
8 0

Answer:

x=-5

Step-by-step explanation:

Combine like terms:

2x+4=-2x-16

4x=-20

Solve

x=-5

n200080 [17]3 years ago
8 0

Subtract xx from 3x3x.

2x+4=5x−16−7x2x+4=5x-16-7x

Subtract 7x7x from 5x5x.

2x+4=−2x−162x+4=-2x-16

Move all terms containing xx to the left side of the equation.

Tap for fewer steps...

Add −2x-2x to both sides of the equation.

2x+4+2x=−162x+4+2x=-16

Add 2x2x and 2x2x.

4x+4=−164x+4=-16

Move all terms not containing xx to the right side of the equation.

Tap for fewer steps...

Subtract 44 from both sides of the equation.

4x=−16−44x=-16-4

Subtract 44 from −16-16.

4x=−204x=-20

Divide each term by 44 and simplify.

Tap for fewer steps...

Divide each term in 4x=−204x=-20 by 44.

4x4=−2044x4=-204

Cancel the common factor of 44.

Cancel the common factor of 44.

Tap for fewer steps...

Cancel the common factor.

4x4=−2044x4=-204

Divide xx by 11.

x=−204x=-204

Divide −20-20 by 44.

x=−5

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Step-by-step explanation:

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3 years ago
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A new 2006 Honda head was values at $25000. It depresides at a rate of 13% a year.
CaHeK987 [17]

Answer:

1. It's value in 2009 was $16,462.575

2. It's value in 2020 will be $3,558.

Step-by-step explanation:

The equation for the value of car after t years has the following format.

V(t) = V(0)(1-r)^{t}

In which V(t) is the value after t years, V(0) is the initial value and r is the ratio of depreciation.

In this problem, we have that:

V(0) = 25000, r = 0.13

So

V(t) = V(0)(1-r)^{t}

V(t) = 25000(1-0.13)^{t}

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1. What was its value in 2009

2009 is 3 years after 2006, so this is V(3)

V(t) = 25000(0.87)^{t}

V(3) = 25000(0.87)^{3}

V(3) = 16462.575

It's value in 2009 was $16,462.575

2.What will be its value in 2020?

2020 is 14 years after 2006, so this is V14)

V(t) = 25000(0.87)^{t}

V(14) = 25000(0.87)^{14}

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Answer:

Step-by-step explanation:

2x-8 ≤ 14

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2. Divide both sides by 2 to get the x alone.

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4. Now, make a line going from the circle to the left and draw an arrow at the end.

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Step-by-step explanation:

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