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QveST [7]
3 years ago
6

Divide the fractions. 9/2 divided by 4/10

Mathematics
2 answers:
mario62 [17]3 years ago
7 0

Answer:

11 1/4

Step-by-step explanation:

9/2/4/10

9/2/2/5

9/2*5/2

45/4

11 1/4

DENIUS [597]3 years ago
5 0

<u>Final Answer:</u>

45/4

<u>Step-by-step explanation:</u>

9/2 ÷ 4/10

  • 9/2 ÷ 10/4
  • 9/2 × 10/4 = 90/8

90/8 ⇒ 45/4

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PLEASE HELPP! The diameter of a decorated plate is 20 centimeters. There is a flower painted every 15.7 centimeters around the e
kirill115 [55]

Answer:

4 flowers

Step-by-step explanation:

First we need to calculate the circumference of the plate.

C = πd

Given

diameter d = 20cm

C = 3.14(20)

C = 62.8 cm

If there is a flower painted every 15.7 centimeters around the edge of the plate, the amount of flower on the plate will be;

Number of flower = Circumference of the plate/length of flower

Amount of flower = 62.8/15.7

Amount of flower = 4

Hence there are 4 flowers painted on the plate

4 0
3 years ago
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Are all trapeziums rhombuses ???​
Agata [3.3K]

Answer:

Yes

Step-by-step explanation:

Because trapezium is just a rhombus in a different form therefore yes.

8 0
4 years ago
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A rectangle with an area of 5/8 ft^2 dilated by a factor of 8.
Lilit [14]

Answer:

40

Step-by-step explanation:

dilated by a factor 8 => the area of a rectangle would be (8x8) times of the origin,

5/8 × (8x8) = 5/8 × 64 = 40 ft²

3 0
3 years ago
What is the rate of return on a $5000 bond purchased at $4750 with a 12% coupon?
Mumz [18]
You earn 12% on the $5000 par value (face value) of the bond. So 0.12*5000 = 600 is the annual coupon payment. You earn $600 each year

This income is divided by the amount you paid to get

600/4750 = 0.1263 which converts to 12.63%

So the answer is choice 2) 12.63%
5 0
3 years ago
A biologist observed that a certain bacterial colony obeys the population growth law and that the colony triples every 4 hours.
MrRa [10]

Answer:

a) P(t) = 2e^{0.275t}

b) 54.225 square centimeters.

c) 2.52 hours

Step-by-step explanation:

The population growth law is:

P(t) = P_{0}e^{rt}

In which P(t) is the population after t hours, P_{0} is the initial population and r is the growth rate, as a decimal.

In this problem, we have that:

The colony occupied 2 square centimeters initially, so P_{0} = 2

The colony triples every 4 hours. So

P(4) = 3P_{0} = 6

(a) An expression for the size P(t) of the colony at any time t.

We have to find the value of r. We can do this by using the P(4) equation.

P(t) = P_{0}e^{rt}

6 = 2e^{4r}

e^{4r} = 3

Applying ln to both sides, we get:

4r = 1.1

r = 0.275

So

P(t) = 2e^{0.275t}

(b) The area occupied by the colony after 12 hours.

P(t) = 2e^{0.275t}

P(12) = 2e^{0.275*12}

P(12) = 54.225

(c) The doubling time for the colony?

t when P(t) = 2P_{0} = 2*2 = 4.

P(t) = 2e^{0.275t}

4 = 2e^{0.275t}

e^{0.275t} = 2

Applying ln to both sides

0.275t = 0.6931

t = 2.52

4 0
3 years ago
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