An acid-base reaction of (r)-sec-butylamine with a racemic mixture of 2-phenylpropanoic acid forms two products having different
melting points and somewhat different solubilities. Draw the structure of these two products. How are the two products related? Be sure to answer all parts.
1 answer:
Answer:
See explanation
Explanation:
When an optically active compound reacts with a racemic mixture, two different products appear .
Hence, when (R)-sec-butylamine reacts with a racemic mixture of 2-phenylpropanoic acid as shown in the image attached.
Enantiomers are optical isomers which are mirror images of each other. The image attached was obtained from Bartleby.
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Answer:
Explanation:
Given that:
The energy of the photon = 2.3 eV
Energy in eV can be converted to energy in J as:
1 eV = 1.60 × 10⁻¹⁹ J
So, Energy =
Considering
Where,
h is Plank's constant having value
c is the speed of light having value
is the wavelength of the light being bombarded
Thus,
Also,
1 m = 10⁻⁹ nm
So,