The gas sample consists of CH₄ and He.
Number of CH₄ moles - 4 g/ 16 g/mol = 0.25 mol
molar volume is where 1 mol of any gas occupies a volume of 22.4 L
Therefore 0.25 mol of CH₄ gas occupies a volume of 22.4 L/mol x 0.25 mol
Volume of methane - 5.6 L
Number of He moles - 2.00 g/ 4 g/mol = 0.5 mol
Volume occupied by He - 22.4 L /mol x 0.5 mol = 11.2 L
The total volume of the sample = 5.6 L + 11.2 L = 16.8 L
Answer:
Ball 16 oz Pint Mason Jar outer dimensions are 5.2 height by 3.2 diameter – which could hold approximately 390 jelly beans. Ball 32 oz Quart Mason Jar outer dimensions are 6.9 height by 3.9 diameter – which could hold approximately 804 jelly beans.Oct 5, 2017
Explanation:
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Focus your attention to the units of the given data and the unit of the final measurement you're going to solve. Through dimensional analysis,you know that the working equation would be:
Food Value = CcalΔT/m
Food value = (6.15 kJ/°C)(1.29 °C)/0.611 g = 12.98 kJ/g
Convert kJ to cal (1 kJ = 239 cal)
Food value = 12.98*239 =<em> 3,103.28 cal/g</em>
Answer:
dtds the temperature of a gas station and the problem is that the volume of a gas station and the temperature and pressure on the volume of emails of the
Explanation:
dyrs the temperature and regards Eric a system generated mail from your intra day of the temperature of the volume and weight and congratulationsgdaftsdttddswhdhj. v of the temperature and the problem please let me to do to get the temperature of a gas station and congratulations Dr suite and I will be in the temperature the temperature of the volume and weight and submit report for the temperature and pressure on the volume and congratulations Dr suite and I'mhsdf to gh
Answer:

Explanation:
Given data:
Number of frame is 12+ 8 = 20
Total filtrate is 360 lb
we know
For 1 plate area 
Then for 20 are PLATE 
filtrate equation is given as

In the above equation only t and A is variable , all other terms are constant
Therefore we have
![\frac{t_2}{t_1}= \frac{A_1}{A_2} = [\frac{65}{105.33}]^2 = 0.36](https://tex.z-dn.net/?f=%5Cfrac%7Bt_2%7D%7Bt_1%7D%3D%20%5Cfrac%7BA_1%7D%7BA_2%7D%20%3D%20%5B%5Cfrac%7B65%7D%7B105.33%7D%5D%5E2%20%3D%200.36)

