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2 years ago

12

Which equation can you use to solve for x?

2 answers:

MrRa [10]2 years ago

6 0

The answer is the first one

ELEN [110]2 years ago

3 0

Answer:

b

Step-by-step explanation:

they are the same angles so they would equal each other

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Find the distance between (-3, 11) and (-6,4).Round to the nearest then the

Likurg_2 [28]

Answer:

d =7.6

Step-by-step explanation:

$(-3,11) =(x_1,y_1)\\(-6,4)=(x_2,y_2)\\\\\mathrm{Compute\:the\:distance\:between\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\\\quad \sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\=\sqrt{\left(-6-\left(-3\right)\right)^2+\left(4-11\right)^2}\\= \sqrt{(-6+3)^2+(4-11)^2}\\ \\d= \sqrt{(-3)^2+(-7)^2} \\\\d = \sqrt{9+49}\\ \\d = \sqrt{58}\\\\d = 7.61577\\\\d =7.6$

3 0

3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

<u>Finding P(A)</u>

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

<u>Finding P(B)</u>

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

<u>Finding $P(A \cap B)$ </u>

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

2 years ago

Name the method that is used to measure irregular shaped objects.

lys-0071 [83]

Answer:

Displacement

Step-by-step explanation:

hope this helps !

5 0

2 years ago

Can someone please help me

Sloan [31]

X= 55 degrees ...........

5 0

3 years ago

find the sums.does the order of the addends matter in an addition sentence? what property is this. -5+6= 6+(-5)=

azamat

In this question we will be using Commutative Law of Addition which is as follows:

The Law that says you can swap numbers around and still get the same answer when you add.

a+b =b+a

where a and b are addends.

Using this law, we can clearly see that order of addends does not matter at all in addition.

Now adding -5+6, we get 6-5 which is equal to 1

Answer is 1

6 0

2 years ago

Read 2 more answers