To find f'(3) (f prime of 3), you must find f' first. f' is the derivative of the function f(x).
Finding the derivative of f(x) = 2x⁴ requires the use of the power rule.
The power rule for derivatives is ![\frac{d}{dx} [x^{n} ] =nx^{n-1}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bx%5E%7Bn%7D%20%5D%20%3Dnx%5E%7Bn-1%7D)
. In other words, you bring the exponent forward and multiply it by the coefficient of the term, and then you subtract 1 from the original exponent.
f'(x) = 
(2x⁴)
f'(x) = 2(4)x³
f'(x) = 8x³
Now, to find f'(3), plug 3 into your derivative.
f'(3) = 8(3)³
f'(3) = 216
<h3>Answer:</h3>
f'(3) = 216
Answer:
$45
Step-by-step explanation:
The sale price changed from $80 to 60, then with the coupon another 25% was taken off leading it to come to a price of $45
$80 x .75 = 60
$60 x .75 = 45
(.75 is for the price of the original value that he will be paying later)
M = (y2-y1)/(x2-x1)
= (4-14)/3-1
= -10/2
= -5
Yshejrhhe is they easiest of them all and as you can see I just can’t fail it bro ik too smart yk it’s y>-3x +1-5
