All categories

3 years ago

Which best describes the relationship between the lines? 2x – y = −7 2x + 4y = 2

Mathematics

2 answers:

seropon [69]3 years ago

8 0

Answer:

Perpendicular

Step-by-step explanation:

2x - y = -7

2x + 4y = 2

-y = -2x - 7

4y = -2x + 2

y = 2x + 7

y = -1/2x + 1/2

Cannot be:

Parallel because the slope would otherwise be the same.

Same line because the equation is not proportional

So, they are perpendicular because a perpendicular line would be a negative and a reciprocal of the current line

ohaa [14]3 years ago

8 0

Answer:

perpendicular

Step-by-step explanation:

You might be interested in

To solve 5/7 - 2/n = 1/21

Usimov [2.4K]

Answer:

the answer is n=3

Step-by-step explanation:

3 0

3 years ago

I need help with #3 ASAP!! Marking brainliest :) Thanks!

Tom [10]

Answer:

the answer is 6x^2

Step-by-step explanation:

goodluck

7 0

3 years ago

What is the half of 14.5

Aleks04 [339]

Answer:

7.25

Explanation:

14.5×½=7.25

3 0

3 years ago

Read 2 more answers

Use the diagram to complete the statement. Triangle J K L is shown. Angle K J L is a right angle. Angle J K L is 52 degrees and

zzz [600]

Answer:

$\bold{sin(38^\circ)=cos(52^\circ)}$

Step-by-step explanation:

Given that $\triangle KJL$ is a right angled triangle.

$\angle JKL = 52^\circ\\\angle KLJ = 38^\circ$

and

$\angle KJL = 90^\circ$

Kindly refer to the attached image of $\triangle KJL$ in which all the given angles are shown.

To find:

sin(38°) = ?

a) cos(38°)

b) cos(52°)

c) tan(38°)

d) tan(52°)

Solution:

Let us use the trigonometric identities in the given $\triangle KJL$ .

We have to find the value of sin(38°).

We know that sine trigonometric identity is given as:

$sin\theta =\dfrac{Perpendicular}{Hypotenuse}$

$sin(\angle JLK) = \dfrac{JK}{KL}\\OR\\sin(38^\circ) = \dfrac{JK}{KL}$ ....... (1)

Now, let us find out the values of trigonometric functions given in options one by one:

$cos\theta =\dfrac{Base}{Hypotenuse}$

$cos(\angle JLK) = \dfrac{JL}{KL}\\OR\\cos(38^\circ) = \dfrac{JL}{KL}$ ....... (2)

By (1) and (2):

sin(38°) $\neq$ cos(38°).

$cos(\angle JKL) = \dfrac{JK}{KL}\\OR\\cos(52^\circ) = \dfrac{JK}{KL}$ ...... (3)

Comparing equations (1) and (3):

we get the both are same.

$\therefore \bold{sin(38^\circ)=cos(52^\circ)}$

6 0

3 years ago

Which represents the solution(s) of the graphed system of equations, y = x2 x – 2 and y = 2x – 2? (–2, 0) and (0, 1) (0, –2) and

Marysya12 [62]

The solution to the system of equation are (0, -2) and (1, 0)

<h3>Solution to system of equations</h3>

System of equations are equations that has unknown and more than 1 equations.

Given the system of equations

y = x^2 + x – 2

y = 2x – 2

Equate both expressions

x^2 + x -2 = 2x - 2
x^2 - x = 0
x(x-1) = 0
x = 0 and x - 1 = 0
x = 0 and 1

If x = 0

y = 0 - 2 = -2

If x = 1

y = 2 - 2 = 0
Hence the solution to the system of equation are (0, -2) and (1, 0)

Learn more on system of equation here: brainly.com/question/13729904

#SPJ4

7 0

2 years ago