All categories

2 years ago

Can someone explain to me how to do this? I will give brainliest.

Mathematics

1 answer:

taurus [48]2 years ago

4 0

Answer:

4x+7 = 19

4x = 19 - 7

4x = 12(divide both sides by 4 to get x)

4x/4 = 12/4

x = 3

Step-by-step explanation:

Like this way you can do all

You might be interested in

Please help Is that right?

Cloud [144]

Answer:

Yep your very smart

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is a predicate of a sentence ? like:

sesenic [268]

$\color{voilet}\huge{AN}$ $\color{yellow}\huge{S}$ $\color{blue}\huge{W}$ $\color{orange}\huge{ER}$

The predicate is (turn yellow in the fall).

⠀

Because the subject in the sentence is the leaves

8 0

2 years ago

Find the roots of h(t) = (139kt)^2 − 69t + 80

Sonbull [250]

Answer:

The positive value of $k$ will result in exactly one real root is approximately 0.028.

Step-by-step explanation:

Let $h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ , roots are those values of $t$ so that $h(t) = 0$ . That is:

$19321\cdot k^{2}\cdot t^{2}-69\cdot t + 80=0$ (1)

Roots are determined analytically by the Quadratic Formula:

$t = \frac{69\pm \sqrt{4761-6182720\cdot k^{2} }}{38642}$

$t = \frac{69}{38642} \pm \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$

The smaller root is $t = \frac{69}{38642} - \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ , and the larger root is $t = \frac{69}{38642} + \sqrt{\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} }$ .

$h(t) = 19321\cdot k^{2}\cdot t^{2}-69\cdot t +80$ has one real root when $\frac{4761}{1493204164}-\frac{80\cdot k^{2}}{19321} = 0$ . Then, we solve the discriminant for $k$ :

$\frac{80\cdot k^{2}}{19321} = \frac{4761}{1493204164}$

$k \approx \pm 0.028$

The positive value of $k$ will result in exactly one real root is approximately 0.028.

7 0

2 years ago

Can someone help me please

Ahat [919]

This is a black screen!!!!

5 0

2 years ago

which three numbers make a right triangle the square root of 4 the square root of 5 the square root of 9 + square root of 6 the

statuscvo [17]

Please, group your sets of numbers, using { } notation or at least semicolons ( ; ). Thanks.

Looking at what I think is your first set: { sqrt(4), sqrt(5), sqrt(16) }

Square each of these and then subst. the results into the Pythagorean Theorem:

{ 4, 5, 16 } Do 4 and 5 when added together result in 16? NO.
Therefore, { sqrt(4), sqrt(5), sqrt(16) } does not produce a right triangle.

Your turn. Pick out the next 3 numbers and test them using the Pyth. Thm.

8 0

2 years ago