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Kamila [148]
3 years ago
5

I am trying to write a c++ program like the game typeracer. When the player starts the program he will be asked to write a sente

nce. I want to divide this sentence into characters so that every time the player hits a key on his keyboard the code will see if he has entered the correct character. Please help! :)
Computers and Technology
1 answer:
murzikaleks [220]3 years ago
6 0
Http://www.cprogramming.com/tutorial/string.html

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Technology can help governments handle economic emergencies, such as the reliance on automation. Crop and resource shortages. Th
uranmaximum [27]

Answer

Technology can help government handle economic emergencies such as crop and resource shortages.

Explanation

The government can address the concerns of food shortages and water scarcity through embracing new technology interventions to increase farm yields and mitigate the impacts of water shortages. Through crop protection methods, weeds and pest can be controlled. Drip irrigation technology applies water directly to the roots of crops to facilitate high crop production. Other technologies to apply can include organic agriculture and integrated soil fertility management.



3 0
3 years ago
Read 2 more answers
Stacy is in the process of creating a storyboard for her personal website, but she is unable to decide which storyboarding techn
Shalnov [3]

Answer:

Webbed storyboard technique

Explanation:

There are several storyboard techniques; however, the best for a website is the webbed storyboard technique.

Coined from the word "web", this technique does not only help in linking pages within the website where a page can be access from other pages, it also links pages of the website to external pages.

An illustration is as follows:

From the homepage of a website, one can access the contact page, the about page, etc.

Each of the listed pages also have link back to the homepage and to every other pages.

5 0
3 years ago
Which Internet protocol (IP) packet fragmentation header field specifies where the fragment belongs in the original datagram
Yanka [14]

An Internet protocol (IP) packet fragmentation header field which specifies where the fragment belongs in the original datagram is the fragment offset.

<h3>What is the TCP/IP model?</h3>

The TCP/IP model is known as the Internet protocol suite or Transmission Control Protocol and Internet Protocol (TCP/IP) model and it can be defined as a standard framework that is designed and developed for the transmission (prepare and forward) of information on the Internet.

In the TCP/IP model, a fragment offset simply refers to an Internet protocol (IP) packet fragmentation header field which is used to specify where the fragment belongs in the original datagram.

Read more on Internet protocol here: brainly.com/question/17387945

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8 0
2 years ago
Create a program that displays a menu to select addition, subtraction, or multiplication. Using random numbers between 0 and 12
Lemur [1.5K]

Answer:

This question is answered using C++

#include<iostream>

#include <cstdlib>

#include <ctime>

using namespace std;

int main(){

   int ope, yourresult;

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

   cout<<"Operator: ";

   cin>>ope;

   srand((unsigned) time(0));

   int num1 = rand() % 12;

   int num2 = rand() % 12;

   int result = 1;

   if(ope == 1){

       cout<<num1<<" + "<<num2<<" = ";

       result = num1 + num2;

   }

   else if(ope == 2){

       cout<<num1<<" - "<<num2<<" = ";

       result = num1 - num2;

   }

   else if(ope == 3){

       cout<<num1<<" * "<<num2<<" = ";

       result = num1 * num2;

   }

   else{

       cout<<"Invalid Operator";

   }

   cin>>yourresult;

   if(yourresult == result){

       cout<<"Correct!";

   }

   else{

       cout<<"Incorrect!";

   }

   return 0;

}

Explanation:

This line declares operator (ope) and user result (yourresult) as integer

   int ope, yourresult;

This prints the menu

   cout<<"Select Operator: \n"<<"1 for addition\n"<<"2 for subtraction\n"<<"3 for multiplication\n";

This prompts the user for operator

   cout<<"Operator: ";

This gets user input for operator

   cin>>ope;

This lets the program generates different random numbers

   srand((unsigned) time(0));

This generates the first random number

   int num1 = rand() % 12;

This generates the second random number

   int num2 = rand() % 12;

This initializes result to 1

   int result = 1;

If the operator selected is 1 (i.e. addition), this prints an addition operation and calculates the actual result

<em>    if(ope == 1){</em>

<em>        cout<<num1<<" + "<<num2<<" = ";</em>

<em>        result = num1 + num2;</em>

<em>    }</em>

If the operator selected is 2 (i.e. subtraction), this prints an subtracttion operation and calculates the actual result

<em>    else if(ope == 2){</em>

<em>        cout<<num1<<" - "<<num2<<" = ";</em>

<em>        result = num1 - num2;</em>

<em>    }</em>

If the operator selected is 3 (i.e. multiplication), this prints an multiplication operation and calculates the actual result

<em>    else if(ope == 3){</em>

<em>        cout<<num1<<" * "<<num2<<" = ";</em>

<em>        result = num1 * num2;</em>

<em>    }</em>

If selected operator is not 1, 2 or 3, the program prints an invalid operator selector

<em>    else{</em>

<em>        cout<<"Invalid Operator";</em>

<em>    }</em>

This gets user input

   cin>>yourresult;

This checks if user result is correct and prints "Correct!"

   if(yourresult == result){

       cout<<"Correct!";

   }

If otherwise, the program prints "Incorrect!"

<em>    else{</em>

<em>        cout<<"Incorrect!";</em>

<em>    }</em>

   return 0;

6 0
3 years ago
“Union-compatible” means that the ____.
Mnenie [13.5K]

Answer:

(c) will be the correct option

Explanation:

Union-compatible : If there are two relations and both have are having same number of attributes then it called union compatibility the domain of similar attributes also must be same for union compatibility. Number of attributes means number of column

so from above discussion it is clear that option (C) will be correct option

3 0
4 years ago
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