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mixer [17]
3 years ago
8

TRIATHLON The course for a local

Mathematics
1 answer:
EastWind [94]3 years ago
3 0

Answer:

Step-by-step explanation:

The course for a local

triathlon has the shape of a right

triangle. This means that one of the angles formed is 90 degrees.

The legs of the triangle consist

of a 4-mile swim and a 10-mile run. These form the opposite side and that adjacent side of the right angle triangle. The hypotenuse of the triangle is the biking portion of the event. We would determine the length of the hypotenuse by applying Pythagoras theorem. It states that

Hypotenuse ^2 = opposite^2 + adjacent ^2

Hypotenuse ^2 = 4^2 + 10^2 = 16 + 100 = 116

Hypotenuse = √116 = 10.77 miles

Approximately 10.8 miles to the nearest tenth.

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Which of the following represents the rate of change for a linear function
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The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow
kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

H_0: \mu = 13252

At the alternative hypothesis, we test if the mean cost has increased, that is:

H_1: \mu > 13252

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that \mu = 13252

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that n = 20, X = 15560, s = 3500

Value of the test statistic:

t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}

t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}

t = 2.95

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

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3 years ago
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Answer:

<em>1/3 > 0.33</em>

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0.333333... > 0.33

1/3 > 0.33

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Which of the following is a statistical question?
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