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strojnjashka [21]
3 years ago
8

if we increased one side of a square by 5 units and decreased the other by 3 units the area of the resulting rectangle would be

21 units squared greater than the area of the square how long are the sides of the original square
Mathematics
1 answer:
zvonat [6]3 years ago
3 0

Answer:

18 units

Step-by-step explanation:

So let's list out the sides.

for the first square let's just call them x

for the second square then they would be x+5 and x-3

So let's write out their areas we will cal the area of the first one z

x*x = z

(x+5)*(x-3) = z+21

since z = x^2 we can set up the second equation as a quadratic.

(x+5)*(x-3) = x^2 + 21

x^2 - 3x + 5x - 15 = x^2 + 21

But look, the x^2s cancel out

2x - 15 = 21

2x = 36

x = 18

Test it out and see if it fits the description, And if you don't understand anything just let me know so I can explain more.  

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sladkih [1.3K]

Answer:

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Step-by-step explanation:

Z is computed from ...

... z = (x -μ)/σ

Our lower limit for x is 184, so its z-value is ...

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Our upper limit for x is 200, so its z-value is ...

... z = (200 -206)/10 = -6/10 = -0.6

A suitable table or probability calculator can tell you ...

... the percent of area associated with z = -2.2 is about 1.4%. That is, about 1.4% of all values lie below z = -2.2.

... the percent of area associated with z = -0.6 is about 27.4%.

The fraction of expenses between $184 and $200 is then calculated to be ...

... 27.4% - 1.4% = 26.0%

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Step-by-step explanation:

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