The probability that a single radar set will detect an enemy plane is 0.9. if we have five radar sets, what is the probability that exactly four sets will detect the plane?
Solution: The given random experiment follows binomial distribution with 
Let x be the number of radar sets that will detect the plane.
We have to find 


Therefore, the probability that exactly four sets will detect the plane is 0.3281
Answer:
Step-by-step explanation:
<1+<2=90 complementary
<1=4 times <2
X+4x=90
5x=90
X=18
<1=18×4=72 degrees
<2=18 degrees
<1=<3 because they are vertical
Do <3= 72
<3+<4=180 because they are supplementary
72+<4=180
<4=108 degrees
<3=72 degrees
Answer:
Each banana cost $0.80.
Step-by-step explanation:
5.20 divided by 6.5 is 0.80
1/2 and 3/8
equivalent
1/2 = 4/8
so 4/8 is greater than 3/8
Answer
5 1/2 is bigger than 5 3/8
Answer:
Your answer is C and D
Step-by-step explanation: