Which programming language are you working in?
Here is how you could achieve this in Python:
establish a counter, starting at 1.
While your counter is 10 or less, do two things:
print the counter,
and increase the counter by 1.
code:
counter = 1
while counter <= 10:
print(counter)
counter = counter + 1
Those last two lines should be indented.
if you follow me and like and mark in brainliest answer only I will tell the answer
Answer:
Double x = 35 / 10;
Explanation:
Java provides simple data types for representing integers, real numbers, characters, and Boolean types. These types are known as _ or fundamental types.
<3
In the C programming language, you can't determine the array size from the parameter, so you have to pass it in as an extra parameter. The solution could be:
#include <stdio.h>
void swaparrayends(int arr[], int nrElements)
{
int temp = arr[0];
arr[0] = arr[nrElements - 1];
arr[nrElements - 1] = temp;
}
void main()
{
int i;
int myArray[] = { 1,2,3,4,5 };
int nrElements = sizeof(myArray) / sizeof(myArray[0]);
swaparrayends(myArray, nrElements);
for (i = 0; i < nrElements; i++)
{
printf("%d ", myArray[i]);
}
getchar();
}
In higher languages like C# it becomes much simpler:
static void Main(string[] args)
{
int[] myArray = {1, 2, 3, 4, 5};
swaparrayends(myArray);
foreach (var el in myArray)
{
Console.Write(el + " ");
}
Console.ReadLine();
}
static void swaparrayends(int[] arr)
{
int temp = arr[0];
arr[0] = arr.Last();
arr[arr.Length - 1] = temp;
}
