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Julli [10]
3 years ago
14

Last month, he sold 50 chickens and 30 ducks for $550. This month, he sold 44chickens and 36 ducks for $532.

Mathematics
1 answer:
melisa1 [442]3 years ago
7 0

Answer: $5.00

Step-by-step explanation:

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Someone just please help me no links no guessing seriously
Doss [256]

Answer:

no I can't u just ruined my mood

8 0
3 years ago
The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and
Delicious77 [7]

The width of rectangle is 2\frac{1}{4}\ cm and length is 5\frac{5}{12}\ cm

Step-by-step explanation:

Let,

Width of rectangle = w

Length of rectangle = w+3\frac{1}{6}=w+\frac{19}{6}

Perimeter of rectangle = 15\frac{1}{3}=\frac{46}{3}\ cm

Perimeter of rectangle = 2(Length + Width)

2(w+\frac{19}{6}+w)=\frac{46}{3}\\2(2w+\frac{19}{6})=\frac{46}{3}\\4w+\frac{19}{3}=\frac{46}{3}

Subtracting \frac{19}{3} from both sides

4w+\frac{19}{3}-\frac{19}{3}=\frac{46}{3}-\frac{19}{3}\\4w=\frac{46-19}{3}\\4w=\frac{27}{3}\\4w=9

Dividing both sides by 4

\frac{4w}{4}=\frac{9}{4}\\w=\frac{9}{4}

Therefore,

Width of rectangle = w = \frac{9}{4}=2\frac{1}{4} cm

Length of rectangle = w+\frac{19}{6}=\frac{9}{4}+\frac{19}{6}=\frac{27+38}{12}=\frac{65}{12}=5\frac{5}{12}\ cm

The width of rectangle is 2\frac{1}{4}\ cm and length is 5\frac{5}{12}\ cm

Keywords: perimeter, addition

Learn more about addition at:

  • brainly.com/question/6270221
  • brainly.com/question/6275033

#LearnwithBrainly

7 0
3 years ago
The two largest lizards in the united states are the gila monster and the chuckwalla. The average gila monster is 0.608 meter lo
Mamont248 [21]

Answer:

Gila Monster is 1.54 times that of Chuckwalla.

Step-by-step explanation:

Given:

Average Length of Gila Monster = 0.608 m

Average Length of Chuckwalla = 0.395 m

We need to find the number of times the Gila monster is as the Chuckwalla.

Solution:

Now we know that;

To find the number of times the Gila monster is as the Chuckwalla we will divide the Average Length of Gila Monster by Average Length of Chuckwalla.

framing in equation form we get;

number of times the Gila monster is as the Chuckwalla = \frac{0.608}{0.395} = 1.5392

Rounding to nearest hundredth's we get;

number of times the Gila monster is as the Chuckwalla = 1.54

Hence Gila Monster is 1.54 times that of Chuckwalla.

5 0
3 years ago
Consider the baggage check-in process of a small airline. Check-in data indicates that from 9am to 10am, 220 passengers checked
Lady bird [3.3K]

Answer:

3.6 minutes.

Step-by-step explanation:

According to the data given in the question, between 9 and 10 AM, 220 passengers have checked in which means that the check-in rate is 3.6 passengers per minute. If the average number of passengers waiting for check-in is 32 and if we assume that the check-in rate is constant throughout the day, then the average passenger had to wait in line for 3.6 minutes.

4 0
3 years ago
Find the measure of unknown angle​
Bumek [7]

Answer:

The angle in the upper right quadrilateral corner = 68 degrees because vertical angles are equal.

Angle Y = 68 (opposite quadrilateral angles are equal).

All quadrilateral angles add to 360 so:

68 + 68 + x + z = 360 = 292

angle X + Z = 292

Therefore angle x = angle z = 146

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
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