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3 years ago

Which equation could be used to find the value of x in the triangle below?

Mathematics

1 answer:

Licemer1 [7]3 years ago

5 0

2x+4x+10+6x-10=180 because all the angles of a triangle equal to 180 so u add up all the angles and set to 180. and x equals 15.

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37. The students at Norton School were asked to name their favorite type of

Bumek [7]

Answer: 60 students

Step-by-step explanation:

So, in the first situation 430 students were surveyed and 258 said that their favourite pet was a dog. The second situation is 100 students and x said that their favourite pet was a dog. We are solving x.

430=258

100= x

Cross multiply

So that is

430 x X= 100x258

430x=25800

Divide both sides by 430

Answer: 60 students

5 0

3 years ago

A collection of 30 gems, all of which are identical in appearance, are supposedto be genuine diamonds, but actually contain 8 wo

levacccp [35]

Answer:

Step-by-step explanation:

From the given information:

There are 30 collections of gems, of which 8 are worthless;

Thus, the number of the genuine diamonds = 30 - 8 = 22.

Let X = random variable;

X consider the value as 0 (for 2 worthless stone selection),

X = 1200(1 worthless stone & 1 genuine stone)

X = 2400 (2 genuine stones selected)

However, the numbers of ways of selecting and chosen Gems can be estimated as:

$(^n_r) = (^{30}_2) \\ \\ \implies \dfrac{30!}{2!(30-2)!} \\ \\ \implies \dfrac{30!}{2!(28)!} \\ \\ \implies \dfrac{30*29*28!}{2!(28)!} \\ \\ \implies \dfrac{30*29}{2*1} \\ \\ \implies 435$

Thus;

$Pr (X = 0) = \dfrac{(^8_2)}{435}$

$Pr (X = 0) = \dfrac{\dfrac{8!}{2!(8-2)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8!}{2!(6)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7*6!}{2!(6)!}}{435} \\ \\ Pr (X = 0) = \dfrac{\dfrac{8*7}{2*1}}{435} \\ \\ Pr (X = 0) = 0.0644$

$P(X =1200) = \dfrac{(^{8}_{1})(^{22}_{1})}{435}$

$P(X =1200) = \dfrac{ \dfrac{8!}{1!(8-1)!}) ( \dfrac{22!}{1!(22-1)!}) }{435}$

$P(X =1200) = \dfrac{ (8) ( 22) }{435}$

$P(X =1200) =0.4046$

$Pr (X = 2400) = \dfrac{(^{22}_2)}{435}$

$Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(22-2)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22!}{2!(20)!}}{435} \\ \\ Pr (X = 2400) = \dfrac{\dfrac{22*21*20!}{2!(20)!}}{435} \\ \\ Pr (X =2400) = \dfrac{\dfrac{22*21}{2*1}}{435} \\ \\ Pr (X = 2400) = 0.5310$

To find E(X):

E(X) = (0 × 0.0644) + (1200 × 0.4046) + (2400 × 0.5310)

E(X) = 0 + 485.52 + 1274.4

E(X) = 1759.92

8 0

3 years ago

Which line is a linear model for the data?

olga2289 [7]

Answer:

Your selected answer is correct.

Step-by-step explanation:

As you can see, the line and the points given follow the same vague path, while the others are below it for the most part, or going the wrong direction.

8 0

2 years ago

Can 171 19/32 be simplified

LenaWriter [7]

171 19/32=(171×32+19)/32=(odd number)/32.

But 32=2⁵

Thus, this ratio cannot be simplified, because the numerator is an odd number.

And the denominator is a power of 2.

7 0

3 years ago

What is the solution to the division problem below you can use long division or synthetic division 2x^3-2x^2-10x-6/ x-3

CaHeK987 [17]

Answer:

Step-by-step explanation:

7 0

3 years ago

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