I hope this helps you
25+10 (12-x)=5 (2x-7)
25+10.12-10x=5.2x-5.7
25+120-10x=10x-35
145-10x=10x-35
145+35=10x+10x
180=20x
x=9
A(n) = a₁.(r)ⁿ⁻¹, where a₁ = 1st term, r= common ratio and n, the rank
In the formula given a₁ = 5, r = 3/2 and n = 6 (we have to find the 6th term value).
a₆ = 5.(3/2)⁶⁻¹ = 5.(3/2)⁵ = 1215/32 (answer C)
In this item, we are to determine the value of x first and substitute the computed value to determine the lengths of QR and QS. Since we are given that two segments are perpendicular bisector of the isosceles triangle then, their lengths should also be equal.
QR = QS
Substituting with the given equation for each.
x/2 + 2 = x - 10
Multiply both sides of the equation by 2,
x + 4 = 2x - 20
Transpose all terms with variables to one side of the equation and the constants to the other.
x - 2x = -20 - 4
-x = -24
x = 24
QR: x/2 + 2 = 24/2 + 2 = 14
QS: x - 10 = 24 - 10 = 14
<em>ANSWER: QR = QS = 14</em>
Answer:
485
Step-by-step explanation: