Answer:
The correct option is O B'
Step-by-step explanation:
We have a quadrilateral with vertices A, B, C and D. A line of reflection is drawn so that A is 6 units away from the line, B is 4 units away from the line, C is 7 units away from the line and D is 9 units away from the line.
Now we perform the reflection and we obtain a new quadrilateral A'B'C'D'.
In order to apply the reflection to the original quadrilateral ABCD, we perform the reflection to all of its points, particularly to its vertices.
Wherever we have a point X and a line of reflection L and we perform the reflection, the new point X' will keep its original distance from the line of reflection (this is an important concept in order to understand the exercise).
I will attach a drawing with an example.
Finally, we only have to look at the vertices and its original distances to answer the question.
The vertice that is closest to the line of reflection is B (the distance is 4 units). We answer O B'
Answer:
Incenter is the answer.
Hope it helps!!!
Step-by-step explanation:
Answer:Consider the right triangle formed by the complex number in the Argand-Gauss plane and it's projections on the axis. – José Siqueira Nov 12 '13 at 17:21
In particular what is the definition of sine of theta in terms of the known sides of the above mentioned right triangle? – Adam Nov 12 '13 at 17:27
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3 Answers
1
Consider the following Argand-diagram
enter image description here
The y-axis is the imaginary axis and the x-axis is the real one. The complex number in question is
x+yi
To figure out θ, consider the right-triangle formed by the two-coordinates on the plane (illustrated in red). Let θ be the angle formed with the real axis.
tanθ=yx
⟹tan−1(yx)
The hypotenuse of the triangle will be
x2+y2−−−−−−√
Therefore,
Step-by-step explanation:
Recursive
formula is one way of solving an arithmetic sequence. It contains the initial
term of a sequence and the implementing rule that serve as a pattern in finding
the next terms. In the
problem given, the 6th term is provided, therefore we can solve for the initial
term in reverse. To make use of it, instead of multiplying 1.025, we should divide it after
deducting 50 (which supposedly is added).
<span>
Therefore, we perform the given formula: A (n) = <span>1.025(an-1) +
50
</span></span>a(5) =1.025 (235.62) + 50 = 291.51
a(4) = 1.025 (181.09) + 50 = 235.62
a(3) = 1.025 (127.89) + 50 = 181.09
a(2) = 1.025 (75.99) + 50 = 127.89
a(1) = 1.025 (25.36) + 50 = 75.99
a(n) = 25.36
The terms before a(6) are indicated above, since a(6) is already given.
So, the correct answer is <span>
A. $25.36, $75.99.</span>
