3 years ago

How would I solve (-2-2i)(-4-3i)(7+8i)

2 answers:

8 0

$(-2-2i)(-4-3i)(7+8i)= \\\\ =(8+6i+8i+6i^2)(7+8i)=\\\\ =(6i^2+14i+8)(7+8i)= \\\\ =42i^2+98i+56+48i^3+112^2+64i= \\\\ =\boxed{48i^3+154i^2+162i+56}$

grin007 [14]3 years ago

3 0

$(-2-2i)(-4-3i)(7+8i)=\\
(-2-2i)(-28-32i-21i+24)=\\
(-2-2i)(-4-53i)=\\
8+106i+8i-106=\\
-98+114i
$

You might be interested in

8 - (-16)<br> What is the answer

Sergeeva-Olga [200]

Answer:

positive 48 ..yan yung pagkakaalam ko

5 0

3 years ago

Read 2 more answers

(please help) Find m

marusya05 [52]

Answer:

$m\angle MLK=78^{\circ}$

Step-by-step explanation:

The Base Angle Theorem states that the base angles of the two equal legs of an isosceles triangle are equal. Since there are 180 degrees in a triangle, we have:

$m\angle MLK+51+51=180,\\m\angle MLK +102=180,\\m\angle MLK=\boxed{78^{\circ}}$

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=6%285-8v%29%2B12%3D-54" id="TexFormula1" title="6(5-8v)+12=-54" alt="6(5-8v)+12=-54" align="ab

Lena [83]

Answer:

$v = 2$

Step-by-step explanation:

$6(5-8v)+12=-54 \\ 30 - 48v + 12 = - 54 \\ 42 - 48v = - 54 \\ - 48v = - 54 - 42 \\ - 48v = - 96 \\ \\ v = \frac{( - 96)}{( - 48)} \\ \\ v = \frac{96}{48} \\ \\ v = 2$