Question

How would I solve (-2-2i)(-4-3i)(7+8i)

Answer 1

$(-2-2i)(-4-3i)(7+8i)= \\\\ =(8+6i+8i+6i^2)(7+8i)=\\\\ =(6i^2+14i+8)(7+8i)= \\\\ =42i^2+98i+56+48i^3+112^2+64i= \\\\ =\boxed{48i^3+154i^2+162i+56}$

Answer 2

$(-2-2i)(-4-3i)(7+8i)=\\ (-2-2i)(-28-32i-21i+24)=\\ (-2-2i)(-4-53i)=\\ 8+106i+8i-106=\\ -98+114i$