3 years ago

How would I solve (-2-2i)(-4-3i)(7+8i)

2 answers:

8 0

$(-2-2i)(-4-3i)(7+8i)= \\\\ =(8+6i+8i+6i^2)(7+8i)=\\\\ =(6i^2+14i+8)(7+8i)= \\\\ =42i^2+98i+56+48i^3+112^2+64i= \\\\ =\boxed{48i^3+154i^2+162i+56}$

grin007 [14]3 years ago

3 0

$(-2-2i)(-4-3i)(7+8i)=\\
(-2-2i)(-28-32i-21i+24)=\\
(-2-2i)(-4-53i)=\\
8+106i+8i-106=\\
-98+114i
$

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