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RSB [31]
3 years ago
5

How would I solve (-2-2i)(-4-3i)(7+8i)

Mathematics
2 answers:
AlexFokin [52]3 years ago
8 0
(-2-2i)(-4-3i)(7+8i)= \\\\ =(8+6i+8i+6i^2)(7+8i)=\\\\ =(6i^2+14i+8)(7+8i)= \\\\ =42i^2+98i+56+48i^3+112^2+64i= \\\\ =\boxed{48i^3+154i^2+162i+56}
grin007 [14]3 years ago
3 0
(-2-2i)(-4-3i)(7+8i)=\\
(-2-2i)(-28-32i-21i+24)=\\
(-2-2i)(-4-53i)=\\
8+106i+8i-106=\\
-98+114i

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Step-by-step explanation:

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