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creativ13 [48]
3 years ago
10

What is the volume of the cone

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0

Answer:

V = 640.6 m³

Step-by-step explanation:

V = ⅓Ah

V = ⅓(πR²h

V = ⅓(3.14)(6²)17

V = 640.56

Rounding to the nearest tenth does not make sense as the other numbers only have precision to the nearest whole number. Had they been reported as R = 6.0 m and h = 17.0 m, MAYBE asking to the nearest tenth would be reasonable. To be very precise, asking to the nearest tenth means the results have four significant digits and the dimensions and π should have been reported as R = 6.000 m, h = 17.00 m and π = 3.142

Furkat [3]3 years ago
7 0

FORMULA:

  • Volume of cone = 1/3πr²h

ANSWER:

So, Volume of given cone = 1/3 × 3.14 × (6)² × 17

  • 640.56m³ or 640.6m³ rounded.

Hence, Volume of given cone is 640.6m³ rounded.

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What is the ratio of the intensities of an earthquake PP wave passing through the Earth and detected at two points 19 kmkm and 4
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Answer:

The ratio of the intensities is roughly 6:1.  

Step-by-step explanation:

The intensity I() of an earthquake wave is given by:

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Hence, the ratio of the intensities of an earthquake wave passing through the Earth and detected at two points 19 km and 46 km from the source is:

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\frac{I_{1}}{I_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

\frac{I_{1}}{I_{2}} = \frac{46 km^{2}}{19 km^{2}}

\frac{I_{1}}{I_{2}} = 5.9:1

Therefore, the ratio of the intensities is roughly 6:1.  

 

I hope it helps you!    

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