Answer:
A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12
Step-by-step explanation:
In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.
x = -b/2a
In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.
3 = -b/2(1)
3 = -b/2
6 = -b
b = -6
Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.
Whole numbers, integers, rational numbers, natural numbers, real numbers
All of those are correct
The perimeter is 96 feet, and 96 X 4.77 = is 457.92
Answer:
https://campussuite-storage.s3.amazonaws.com/prod/735181/c9be791c-b8dc-11e6-bf0d-22000bd8490f/1815482/64a2070e-a58b-11e8-be02-0a844dce770e/file/Homework_Helper-Grade_5_Module_5.pdfStep-by-step explanation: sorry for the link but that should help
