The solutions to the system of equations are (-2,-6) and (4,6)
<h3>How to determine the system of equations?</h3>
We have:
-2x + y = -2
Next, we plot the graph of both functions.
From the attached graph, the equations intersect at (-2,-6) and (4,6)
Hence, the solutions to the system of equations are (-2,-6) and (4,6)
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Answer:
Step-by-step explanation:
Th correct one is the third box
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Answer:
0,11
Step-by-step explanation:
y^2-11y=0
y(y-11)=0 we have transformed the equation into a product
a product can be zero only if one of the factors is 0
so the two solutions are
y=0
and y-11=0 y=11
Sina - (cosa)(tanb)/cosa + (sina)(tanb)
sina ≡ (tana)(cosa)
(tana)(cosa) - (cosa)(tanb)/cosa + (tana)(cosa)(tanb)
= cosa(tana - tanb)/cosa(1 + tanatanb)
(cosas cancel out)
= (tana - tanb)/(1 + tanatanb) ≡ tan(a-b)
You seem to have forgotten to add in the y-intercept or slope. For the information you have given, it could be any equation, so long as it passes through the point (2, -1), such as
y = -x + 1
