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jekas [21]
3 years ago
5

Answer these 2 questions if ur smart?!?!?

Mathematics
2 answers:
Mariulka [41]3 years ago
8 0

1. (4x+5y)(2x-3y)+3xy= 4x*2x-4x*3y+5y*2x-5y*3y+3xy=8x^2-12xy+10xy-15y^2+3xy= 8x^2+xy-15y^2

2. (2x^2+3)(4x+5)-8x(x^2-2)=2x^2*4x+2x^2*5+3*4x+3*5-8x*x^2+8x*2=

=8x^3+10x^2+12x+15-8x^3+16x=

=10x^2+28x+15

Aleks [24]3 years ago
8 0

Answer:

1. 8x^2+xy-15y^2           2. 10x^2 + 28x + 15

Step-by-step explanation:

For Question 1:

(4x + 5y) (2x - 3y) + 3xy

= 8x^2 - 12xy + 10xy - 15y^2 + 3xy

=8x^2+xy-15y^2       (cannot simplify any further)

For Question 2:

(2x^2 + 3)(4x +5) - 8x(x^2 -2)

=8x^3 + 10x^2 + 12x + 15 - 8x^3 + 16x

=10x^2 + 28x + 15         (cannot simplify any further)

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So far this season, Shawn has averaged 4 out of 11 free throws per game. Based on his previous performance, how many free throws
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8

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5 0
3 years ago
The school production of Our Town' was a big success. For opening night. 434 tickets were sold. Students paid $4.00 each, while
Alex73 [517]

Answer:

286 students attended

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Step-by-step explanation:

Given

Tickets = 434

Students = \$4.00

Non-Students = \$6.00

Total = \$2032.00

Solving (a): Number of students

Represent students with S and non students with N

So:

S + N = 434 --- (1)

4S + 6N = 2032 --- (2)

Make N the subject of formula in (1)

N = 434 - S

Substitute 434 - S for N in (2)

4S +6(434 - S) = 2032

Open Bracket

4S + 2604 - 6S = 2032

Collect Like Terms

4S - 6S = 2032 - 2604

-2S = -572

Divide through by -2

S = 286

<em>Hence; 286 students attended</em>

Solving (b):

Recall that

N = 434 - S

N = 434 - 286

N = 148

<em>148 non students attended</em>

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