A(1) = -6 +(1 -1)*(1/5) = -6
A(4) = -6 +(4 -1)*(1/5) = -5 2/5
A(10) = -6 +(10 -1)*(1/5) = -4 1/5
Answer:
X^2-2X+1=0
Step-by-step explanation:
given,2X-X^2=1
or,-(X^2-2X)=1
or,X^2-2X=-1
or,X^2-2X+1=0 ,which is the req.equation in standard form.
We are given the function f(x) = x + 5 in which the abscissa chosen is at x = 4w. To find the ordinate or the y-component, we replace x with 4w in the equation given. In this case, y = 4w + 5. Hence the answer to this problem is B. (4w, 4w + 5)
<h2> the answer isthe value of x=20°</h2>
P=focal legnth is the distance from the focus to the vertex, which also is the disance from the directix to the vertex
therefor
distance from directix to focus=2 times focal legnth
find distance
horizontal distance
from y=-0.6 to y=2.6, that is distance ot 3 units
3/2=1.5
focal distance=1.5