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a_sh-v [17]
3 years ago
11

PLEASE HELP!!!! ASAP!!!! THANK!!! Which ordered pair is a part of the solution set of 2x+y>5

Mathematics
1 answer:
kvv77 [185]3 years ago
4 0

Answer:

I can't find one of these

Step-by-step explanation:

In my way:

let x=0

2 (0)+y=5

y=5

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Write an expression with 4 terms , containing the coefficients 3,6, and 9
Vaselesa [24]
4x^3+6x^2-9x+1 is an example
3 0
3 years ago
If I put 4736 marbles into groups of 100, how many groups would I have? Show how you figured it out.
NNADVOKAT [17]
Divide to find out

4736/100 = 47.36

Therefore, we have  to round, and then we get 47. 

Answer: 47 groups and a remainder of 36. 
8 0
3 years ago
Read 2 more answers
M ÷ n - 3 (m + n) with m=-10 and n=-2
avanturin [10]
Given:
m/n-3(m+n)
m=-10 and n=-2

Solving:

-10/-2-3(-10-2) Since m=-10 and n=-2, we substitute them in for the values since they have an equal relationship.

Now, follow Orders of Operations: PEMDAS


-10/-2-3(-12) Simplify parentheses (P)
There are no Exponents (E)
Multiplication (M) and Division (D) are =, so we do whatever operation comes from the left to right.
-10/-2=5 Division comes first on the left.
therefore:
5-3(-12)

-3(12)=-36, Multiplication is last on the right.
therefore:
5-36

5-36=-31 After M/D, we do Addition and Subtraction, which are also =, so we do them left to right.

Therefore -10/-2-3(-10-2)=-31
3 0
3 years ago
Simplify<br><br> Will give brainiest to person who solves all the problems in picture.
Reika [66]

Answer:

\sqrt{10+4\sqrt{6 } = 4.44948

or = \sqrt{6}  + 2

<em>step by step...solving </em>

<em>10 + 4</em>\sqrt{6}<em />

<em>add/subtract </em>\sqrt{6}<em>² = 6</em>

<em>=10 + 4</em>\sqrt{6}<em> + </em>\sqrt{6}<em>² - 6</em>

<em>Refine</em>

<em>= </em>\sqrt{6}<em> ² + 4</em>\sqrt{6}<em> + 4</em>

<em>rewrite </em><em>↑</em><em> as </em>\sqrt{6}<em>² + 2</em>\sqrt{6}<em> * 2 + 2²</em>

<em>apply Perfect Square Formula (a + b)² = a² + 2ab +²</em>

<em>a = </em>\sqrt{6}<em>, b=2</em>

<em>= (</em>\sqrt{6}<em> + 2)²</em>

<em>= </em>\sqrt \sqrt({6}+ 2)<em>2square    </em>

<em>(the 2 square would not fit like i wanted it to)</em>

<em>apply radical rule </em>\sqrt[n]{a^{n} } = a<em>, assuming a ≥ 0</em>

<em>= </em>\sqrt{6} + 2<em />

posting others as picture (have an account with Symbolab to help me as well.  Just taking too long to type in the step by step if you need it.  all pictures have the decimal result.

5 0
4 years ago
Jessica and Robert have two young children. They have $7,000 of qualified child care expenses and an AGI of $22,000 in 2019. Wha
Effectus [21]

Answer:

$1,860

Step-by-step explanation:

The 20%-35% from up to $6,000 of expenses paid for two or more Qualifying Persons. The percentage falls by 1% for every additional $2,000 of income until it reaches 20%.

22,000+7,000-6,000-15,000=8000/2000= 4%

35%-4%= 31%

31% × $6,000, the maximum qualified child care.

$1,860

6 0
3 years ago
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