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fiasKO [112]
3 years ago
5

I need help with number 1

Mathematics
1 answer:
blsea [12.9K]3 years ago
4 0

The top and bottom faces are each 4-ft by 4-ft. 
Their areas are each (4 x 4) = 16 ft².
Total for top and bottom faces = (2 x 16 ft²) = 32 ft².

All four side-faces are 4-ft by 10-ft.
Their areas are each (4 x 10) = 40 ft².
Total for the four side faces = (4 x 40 ft²) = 160 ft² .

Total area of      (top and bottom) + (4 sides) =

                                      32 ft²   +   160 ft²   =   <em>192 ft²


</em>
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Given that A=27, B=43 and c=17, solve triangle ABC to the nearest hundredth
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When we are given 3 sides, we try to solve the angles first by using the
law of cosines
cos (A) = [b^2 + c^2 - a^2] / (2 * b * c)
cos (A) = [43^2 + 17^2 -27^2] / (2 * 43 * 17)
cos (A) = [1,849 + 289 -729] / <span> <span> <span> 1,462
</span></span></span>cos (A) = 1,409 / 1,462
cos (A) = <span> <span> <span> 0.96374829001368
Angle A = 15.475

Now that we have one angle, we next can use the
Law of Sines
sin(B) / side b = sin(A) / side a
sin(B) = sin(A) * sideb / sidea
</span></span></span><span>sin(B) = sin(15.475) * 43 / 27
</span><span>sin(B) = 0.26682 * 43 / 27
sin (B) = </span><span>0.424935555555</span>
Angle B = 25.147 Degrees
Remember the arc sine (<span>0.424935555555) also equals </span> <span> <span> <span> 154.85

</span></span></span>Finally, calculating the third angle is quite easy
Angle C =  180 - Angle (A) - Angle(B)
Angle C =  180 - 15.475 - 154.85
Angle C =  9.675

Source:
http://www.1728.org/trigtut2.htm


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