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3 years ago

Henri surveys his 20 classmates about the number of times they go swimming per week during the summer.

Mathematics

2 answers:

miv72 [106K]3 years ago

4 0

I just took ths in a test and the answer is C greater

timofeeve [1]3 years ago

3 0

D. You need the data values to figure it out

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A total of 766 tickets were sold for the school play. They were either adult tickets or student tickets. There were 66 more stud

Svetllana [295]

350 because 350+416=766

8 0

3 years ago

There are 16 students who are participating in a chess tournament. The players will be randomly chosen. What is the probability

Ainat [17]

2/16 which is equal to 1/8 or 0.125

6 0

2 years ago

Plz help me with this plz

const2013 [10]

Answer:

Slope: $-\frac{3}{4}$

Y intercept: 7

Equation: $y=-\frac{3}{4}x+7$

Step-by-step explanation:

The slope is found by doing the equation $\frac{rise}{run}$ . When looking at the first two points, it's shown that the rise (difference between the two y values) is -3 (since it decreased by 3) and the run (difference between the two x values) is 4 (since it increased by 4).

This gives us a slope of $-\frac{3}{4}$ .

The y intercept is found by looking at the y value when x = 0. In this picture, it is clear that it is 7.

The equation you want to use is y = mx + b , where b is the y intercept and m is the slope. Just plug in the numbers and you got your equation!

7 0

3 years ago

What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2? (5 points)

tiny-mole [99]

The third choice is appropriate.
an = 5 - 3(n - 1); all integers n ≥ 1

_____
This equation follows the form for the general term of an arithmetic sequence.
an = a1 + d(n - 1)
where a1 is the first term (corresponding to n=1), and d is the common difference. From the problem statement, a1 = 5 and d = 2 - 5 = -3.

6 0

2 years ago

2. An exam readiness awareness taskforce at a Fremont National university sampled 200 students after the midterm to ask them whe

k0ka [10]

Answer:

c) (40+60+25)/200 or 63%

Step-by-step explanation:

n= 200 students

Did Well on the Midterm and Studied for the Midterm = 75

Did Well on the Midterm and Went Partying = 40

Did Poorly on the Midterm and Studied for the Midterm = 25

Did Poorly on the Midterm and Went Partying = 60

The number of students that did poorly on the midterm or went partying the weekend before the midterm is given by the sum of all students who did poorly to all students who went partying minus the number of students who did Poorly on the Midterm and Went Partying:

$N=(25+60)+(40+60) - 60\\N= 125$

The probability that a randomly selected student did poorly on the midterm or went partying the weekend before the midterm is given by:

$P = \frac{N}{n}=\frac{125}{200} = 0.63 = 63\%$

3 0

2 years ago