Answer:
22 3/4 ft
Step-by-step explanation:
The diagram seems to show a 6 1/2 ft person casting a 9 ft shadow at the same time a flagpole is casting a 31 1/2 ft shadow. You want the height of the flagpole.
<h3>Proportion</h3>
Shadow lengths are presumed proportional to the height of the object making them. This means ...
h/(31 1/2) = (6 1/2)/9 . . . . . all lengths in feet
Multiplying by 31 1/2, we get ...
h = (31 1/2)(6 1/2)/9 = (819/4)/9 = 91/4
h = 22 3/4 . . . . ft
The flagpole is 22 3/4 feet tall.
Answer:
Let's define the variables:
A = price of one adult ticket.
S = price of one student ticket.
We know that:
"On the first day of ticket sales the school sold 1 adult ticket and 6 student tickets for a total of $69."
1*A + 6*S = $69
"The school took in $150 on the second day by selling 7 adult tickets and student tickets"
7*A + 7*S = $150
Then we have a system of equations:
A + 6*S = $69
7*A + 7*S = $150.
To solve this, we should start by isolating one variable in one of the equations, let's isolate A in the first equation:
A = $69 - 6*S
Now let's replace this in the other equation:
7*($69 - 6*S) + 7*S = $150
Now we can solve this for S.
$483 - 42*S + 7*S = $150
$483 - 35*S = $150
$483 - $150 = 35*S
$333 = 35*S
$333/35 = S
$9.51 = S
That we could round to $9.50
That is the price of one student ticket.
Step-by-step explanation:
If the die has 6 sides, this will be 10 or under, but there are 2160 ways this can happen