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Sonbull [250]
4 years ago
5

Is the answer indefinite, zero, or infinite? 3x - 2 + 2x - 3

Mathematics
2 answers:
jenyasd209 [6]4 years ago
8 0
The answer is Indefinite
Nezavi [6.7K]4 years ago
7 0

Answer:

x-5

Step-by-step explanation:

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The coordinate points of triangle ABC are A(5,0), B(2,1), and C(-4,-4). If the triangle is translated 8 units right and 5 units
Studentka2010 [4]

Answer:

A(13,-5)

B(10,-4)

C(4,-9)

Step-by-step explanation:

Translation of 8 units right >>> affects the "x" coordinate. Add 8 to each x coordinate.

Translation of 5 units down >>> affects the "y" coordinate. Subtract 5 from each y coordinate.

The coordinates are:

A (5,0)

B (2,1)

C (-4,-4)

New coordinates would be:

A (5+8,0-5)

B(2+8,1-5)

C(-4+8,-4-5)

Hence,

A(13,-5)

B(10,-4)

C(4,-9)

These are the new coordinates after the translation given.

6 0
3 years ago
Can someone help please!
Tcecarenko [31]

Answer:

7*(1/10)=   the third one

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
How do I solve this problem?
umka2103 [35]

Answer:

theta = all real values

Step-by-step explanation:

sec theta + tan theta  = cos theta / (1-sin theta )

sec theta = 1/cos theta

tan theta = sin theta/cos theta

1/cos theta + sin theta /cos theta= cos theta/ (1-sin theta)

(1+ sin theta) / cos theta = cos theta /( 1-sin theta)

using cross products

(1+sin theta) * (1-sin theta) = cos theta * cos theta

1 +sin theta - sin theta- sin^2 theta= cos ^2 theta

1 - sin ^2 theta= cos ^2 theta

cos ^2  theta= cos ^2 theta

this is an identity so it is true for all theta

7 0
3 years ago
3х + 5 2х +9<br> х? – 4х + 3х2 – 9<br> Help
Brums [2.3K]

the answers for this will be x=2

8 0
3 years ago
The mass of a radioactive element at time x is given by the equation below, where c is the original mass and h is the half-life
krek1111 [17]
\bf M(x)=c(0.5)^{\frac{x}{h}}\implies 10=36(0.5)^{\frac{x}{4.9}}\implies \cfrac{10}{36}=0.5^{\frac{x}{4.9}}&#10;\\\\\\&#10;\cfrac{5}{18}=0.5^{\frac{x}{4.9}}\implies log\left( \frac{5}{18} \right)=log\left( 0.5^{\frac{x}{4.9}} \right)&#10;\\\\\\&#10;log\left( \frac{5}{18} \right)={\frac{x}{4.9}}\cdot  log\left( 0.5 \right)\implies &#10;\cfrac{4.9\cdot  log\left( \frac{5}{18} \right)}{log(0.5)}=x
5 0
3 years ago
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