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S_A_V [24]
2 years ago
6

Jim, Katrina, Larry, and Jim have all been invited to a dinner party. They arrive randomly and each person arrives at a differen

t time.
a. In how many ways can they​ arrive?
b. In how many ways can Jim arrive first and Kim ​last?
c. Find the probability that Jim will arrive first and Kim last.

a.___ (Type an integer)
b.___ (Type an integer.)
c.___ (Type a fraction. Simplify your answer)
Mathematics
2 answers:
tino4ka555 [31]2 years ago
7 0

Answer:

24

6

1/12

Step-by-step explanation:

a) This is a counting problem 4*3*2*1 = 24 different ways.

b) 1 * 2 * 1 * 1   = 2 ways

This is one you should try.

Jim Kat Larry Kim

Jim Larry Kat Kim

You can't get another way.

c)

There are 2 ways that Jim can arrive first and Kim Last shown in b

2/24 = 1/12

DaniilM [7]2 years ago
3 0

Answer:

i) 4!=24

ii) 2 ways

iii) 2/24=1/12

Answered by gauthmath.

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Answer:

t _{critical} = 1.760

t = 2.2450

d. 0.264

Step-by-step explanation:

The null hypothesis is:

H_o: \mu_1 - \mu_2 = 0

Alternative hypothesis;

H_a : \mu_1 - \mu_2 > 0\\

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The percentage of the variance is;

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