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Elenna [48]
3 years ago
13

Mr. O'Connor had $90 to spend at a football game. He spent 31/45 on his ticket. Then, he spent 3/7 of his remaining money at the

concession stand. While walking back to his seat, he saw a new hat on sale for $18. Did Mr. O'Connor have enough money left to buy the hat? Show all your work
Mathematics
1 answer:
Kobotan [32]3 years ago
4 0

He has $90 in total to spend

He spent (31/45) of this money on ticket

so money spent on ticket =(31/45) *90 =2790/45 =62

Now money left with him is 90-62 =28 $

Now it says that he spent (3/7) of this remaining money at concession stand

so money spent on concession stand =(3/7)*28 =84/7 =12

Now money left with him = 28-12 =16

So money left with him is $16 but hat costs for $18

So Mr. O'Connor didnt have enough moeny to buy the hat

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4 0
3 years ago
Read 2 more answers
Factorise 6x²-14x-12​
maksim [4K]

Answer:

2(x - 3)(3x + 2)

Step-by-step explanation:

Given

6x² - 14x - 12 ← factor out 2 from each term

= 2(3x² - 7x - 6) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term.

product = 3 × - 6 = - 18 and sum = - 7

The factors are - 9 and + 2

Use these factors to split the x- term

3x² - 9x + 2x - 6 ( factor the first/second and third/fourth terms )

= 3x(x - 3) + 2(x - 3) ← factor out (x - 3) from each term

= (x - 3)(3x + 2)

Thus

3x² - 7x - 6 = (x - 3)(3x + 2) and

6x² - 14x - 12 = 2(x - 3)(3x + 2) ← in factored form

8 0
3 years ago
Bags are filled with bird food at a rate of 420 grams per second.
Eduardwww [97]

Answer:

302

Step-by-step explanation:

420(grams per sec)x60(seconds in a min) = 25,200(grams per min)

25,200x60(min in an hour) = 1,512,000(grams an hour)

1,512,000/1,000(grams in a kilogram) = 1,512 (kilograms per hour)

1,512/20 (size of bag) = 75.6 (bags filled per hour)

75.6x4(hours elapsed asked by the question) = 302 bags completly filled in 4 hours

3 0
2 years ago
Tahmid has 96 G.I. Joe action figures and Sandeep has one-third as much as Tahmid does. How many figures must Tahmid give Sandee
Ann [662]
Tahmid has 96 figures, Sandeep has 1/3 of it so 
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Sandeep has 32 figures

Tahmid 96 ; Sandeep 32

How many must tahmid give so they have the same figures?
First take the difference of the two so we know how many tahmid can give. 
96-32 = 64
now they each have 32 and 64 give or keep. for each one tahmid gives, he must keep one himself so to match the number they both own. so we divide the number of 2, one part to give, the other part to keep himself.
64/2 = 32
So, Tahmid must give Sandeep 32 figures to have equal number of figures of 64 each. 
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Makovka662 [10]
Hello,

Answer:

1) given equation
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5) multiplication or division property of equality

Explanation:

Hope this helps!
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