The amount that the bank loaned out at 7.9% is $1,574.00
How do represent the amounts lent at different rates?
On the assumption that x amount was loaned at 7.9% and that the remaining amount, (8,200-x) was loan out at 7.4%, we can determine the interest charged on each loan as the loan multiplied by the interest rate
interest on 7.9% loan=7.9%*x=0.079x
interest on 7.4% loan=7.4%*(8200-x)
interest on 7.4% loan=606.80-0.074x
total interest=0.079x+606.80-0.074x
total interest=0.005x+606.80
total interest on loans=614.67
614.67=0.005x+606.80
614.67-606.80=0.005x
7.87=0.005x
x=7.87/0.005
x=amount loaned at 7.9%=$1,574.00
y=$8200-$1574
y=$6,626.00
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Answer:
y=3/5*x, A(0,0), B(1,3/5), C(2,6/5)
Step-by-step explanation:
A(5,3)=(x1,y1)....x1=5, y1=3
m=3/5
y-y1=m(x-x1)
y-3=3/5(x-5)
y-3=3/5*x-3/5*5
y-3=3/5*x - 3
y=3/5*x-3+3
y=3/5*x
x=0, y=3/5*x, y=3/5*0=0 A(0,0)
x=1, y=3/5*1=3/5 B(1,3/5)
x=2, y=3/5*2=6/5 C(2,6/5)
Mean
7 days
add them up and divide by 7
50+56+52+46+48+42+38=332
divide that by 7
47.428 about
distance each is from the mean
50 is 2.572 from it
56 is 8.572 from it
52 is 4.572 from it
46 is 1.428 from it
48 is 0.562 from it
42 is 5.428 from it
38 is 9.428 from it
add those and average them
(2.572+8.572+4.572+1.428+0.562+5.428+9.428)/7=4.652
absolute deviation is 4.652 aprox
