By the distribution,6.3 minutes is the time limit that 75.8% of college students go over when looking for a parking space in the library parking lot.
Given that,
Finding a parking spot in the library parking lot takes college students an average of 7.0 minutes, with a standard deviation of 1 minute, according to a normal distribution.
Find the window of opportunity that 75.8% of college students miss when looking for a place in the library parking lot.
The following formula calculates the z-score of a measure X of a normally distributed variable with mean μ and standard deviationσ:
Z=(X-μ)/σ
The z-score calculates how far the measure deviates from the mean by standard deviation.
The p-value for this z-score, which is the percentile of X, can be obtained by looking at the z-score table.
The cut-off time is the 100th percentile minus 75.8th percentile, or X, for Z = -0.7, so:
Z=(X-μ)/σ
-0.7=(X-7)/1
-0.7=X-7
X=-0.7+7
X=6.3
Therefore, 6.3 minutes is the time limit that 75.8% of college students go over when looking for a parking space in the library parking lot.
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Answer:
48 crayons
Step-by-step explanation:
There are 6 boxes total, each with 8 crayons in them. Notice that if you would count all the crayons, you would add 8 to the total number of crayons each time you counted a box. There are 6 boxes, so that would be equivalent to adding 8 a total of six times. You would use multiplication: 6 x 8 which is 48.
Answer:
78
Step-by-step explanation:
11 + x = 89 Subtract 11
11 - 11 + x = 89 -11
x = 78
Answer:
plz like and rate
Step-by-step explanation:
Find the nth term of this number sequence.
2 8 14 20 26
Again write the numbers 1 to 5 above the numbers in the sequence, and leave a spare line again.
n 1 2 3 4 5 (1st row)
(2nd row)
2 8 14 20 26 (3rd row)
Since the sequence is going up by 6, write down your multiples of 6 on the 2nd row.
n 1 2 3 4 5 (1st row)
6n 6 12 18 24 30 (2nd row)
2 8 14 20 26 (3rd row)
Now, to get the numbers in the 3rd row from the 2nd row take off 4.
So, to get from the position numbers (n) to the numbers in the sequence you have to times the position numbers by 6 and take off 4.
Therefore, the nth term = 6n – 4
