The only definite number we can tell you is that in order to lift
a 100kg box, you have to somehow provide a force of about
980 newtons (about 220 pounds) pointing upward. That's the
weight of the box, and you have to lift with at least that much force
just to get the box off the ground.
After that, the answer to your question is 'YES'. The time it takes
depends on how much force you have available, how far you want
to lift the box, and how fast.
Here are the Physics formulas you have to use:
-- The amount of "Work" you'll do is
(the amount of force you use) times (how far up you lift the box) .
-- The "Power" (amount of watts) you'll use is
(the amount of 'work' you do) divided by (the length of time it takes).
So ...
-- The higher you lift the box, the more 'work' your lift-machine does.
-- The faster the box is lifted, the more 'power' your lift-machine needs.
Answer:
a. A = 0.0859 m^2
b. A = 0.0178 m^2
Explanation:
Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.47 T. When viewed edge-on, the first surface is tilted at an angle of from the horizontal, and a net magnetic flux of 8.4 103 Wb passes through it. The same net magnetic flux passes through the second surface. (a) Determine the area of the first surface. (b) Find the smallest possible value for the area of the second surface.
take note that the question has not specified th angle which the surface is tilted so i assume the angle is at
to the horizontal
flux = BAcos(
)
B=magnetic flux in Weber
A=area of the flat surface in m^2
=the angle to the horizontal
a) 8.4 x10^-3= (.47)Acos(78)
alpha has to be the angle from the normal and not the horizontal so 90-12=78,
8.4 x10^-3
/(.47)cos(78)
A = 0.0859 m^2
b) If flux remains the same then for it to be the smallest possible area it needs to be perpendicular to the magnetic field so alpha would be 0.
8.4 x10^-3 = (.47)Acos(0)
A = 0.0178 m^2