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3 years ago

How much current will a 500 W vacuum cleaner draw if it has a resistance of 30Ω?

Physics

1 answer:

Fynjy0 [20]3 years ago

4 0

Answer:

4.2 amps, factoring in resistance roughly 4.1

Explanation:

I'm assuming here that were talking standard voltage thats its most houses so 120 volts, atleast in the U.S.

So you need to find x=amps

Watts is calculated by volts x current (Amps)

You have the watts and the "Voltage"

Just do 500/120 and you get 4.166666667 and you can round that to 4.2amps if you just want it in the simple form.

Hope this helped :)

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Can 200 watts lift a 100 kg box,and if so how long would it take?

topjm [15]

The only definite number we can tell you is that in order to lift
a 100kg box, you have to somehow provide a force of about
980 newtons (about 220 pounds) pointing upward. That's the
weight of the box, and you have to lift with at least that much force
just to get the box off the ground.

After that, the answer to your question is 'YES'. The time it takes
depends on how much force you have available, how far you want
to lift the box, and how fast.

Here are the Physics formulas you have to use:

-- The amount of "Work" you'll do is

(the amount of force you use) times (how far up you lift the box) .

-- The "Power" (amount of watts) you'll use is

(the amount of 'work' you do) divided by (the length of time it takes).

So ...

-- The higher you lift the box, the more 'work' your lift-machine does.

-- The faster the box is lifted, the more 'power' your lift-machine needs.

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4 years ago

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Explanation:

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4 years ago

A plane can fly 390 miles in the same time as it takes a car to go 120 miles. If the car travels 90 mph slower than the plane, f

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3 years ago

Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.47 T. When viewed edge-on, the first surfac

alexgriva [62]

Answer:

a. A = 0.0859 m^2

b. A = 0.0178 m^2

Explanation:

Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.47 T. When viewed edge-on, the first surface is tilted at an angle of from the horizontal, and a net magnetic flux of 8.4 103 Wb passes through it. The same net magnetic flux passes through the second surface. (a) Determine the area of the first surface. (b) Find the smallest possible value for the area of the second surface.

take note that the question has not specified th angle which the surface is tilted so i assume the angle is at $12^{0}$ to the horizontal

flux = BAcos( $\alpha$ )

B=magnetic flux in Weber

A=area of the flat surface in m^2

$\alpha$ =the angle to the horizontal

a) 8.4 x10^-3= (.47)Acos(78)

alpha has to be the angle from the normal and not the horizontal so 90-12=78,

8.4 x10^-3

/(.47)cos(78)

A = 0.0859 m^2

b) If flux remains the same then for it to be the smallest possible area it needs to be perpendicular to the magnetic field so alpha would be 0.

8.4 x10^-3 = (.47)Acos(0)

A = 0.0178 m^2

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4 years ago